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What is y(x) given that d²y dx² +4e-2x = 0 where you have the boundary conditions: dy dx y = yo (a constant) at x=0 You have to integrate twice as this is a second order differential equation so you need two boundary conditions to get the complete solution. (Most people are better at differentiating then integrating so check your answer by differentiating it!) = q (a constant) at x=0

What is y(x) given that d²y dx² +4e-2x = 0 where you have the boundary conditions: dy dx y = yo (a constant) at x=0 You have to integrate twice as this is a second order differential equation so you need two boundary conditions to get the complete solution. (Most people are better at differentiating then integrating so check your answer by differentiating it!) = q (a constant) at x=0

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What is y(x) given that d²y dx² +4e-2x = 0 where you have the boundary conditions: dy dx y = yo (a constant) at You have to integrate twice as this is a second order differential equation so you need two boundary conditions to get the complete solution. (Most people are better at differentiating then integrating so check your answer by differentiating it!) = q (a constant) at x = 0 x = 0
Transcribed Image Text:What is y(x) given that d²y dx² +4e-2x = 0 where you have the boundary conditions: dy dx y = yo (a constant) at You have to integrate twice as this is a second order differential equation so you need two boundary conditions to get the complete solution. (Most people are better at differentiating then integrating so check your answer by differentiating it!) = q (a constant) at x = 0 x = 0
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