What is the z* critical value for constructing a 94% confidence interval for one proportion? This value is not listed on the t distribution table, so you will need to use this z-table to determine the value.

Q: se the confidence interval to find the margin of error and the sample mean.   (0.656,0.800)…

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Q: A DNP student wants to evaluate the change in knowledge scores of a group of cardiac patients after…

A: In given problem, a DNP student obtains a pretest at the beginning of class and immediately after…

Q: You sample 36 families to find out how much they spent on groceries last month. Your sample mean is…

A: Given data,n=36x=540s=82α=0.05

Q: You intend to estimate a population mean with a confidence interval. You believe the population to…

A: Sample size (n) = 63 Degree of freedom = n – 1 = 63 – 1 = 62 Confidence level = 81.2% Level of…

Q: AT scores are distributed with a mean of 1,500 and a standard devieation of 287. You are interested…

A: Given that, Critical value: Using the z-table, the critical value at 85% confidence level is ,

Q: When solving a problem related to one sample and the confidence interval of variance. Which table…

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Q: Find the margin of error for the confidence interval of population proportion. Lower bound  0.135.…

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Q: Describe the t test for 2 independent samples.

A: In order to assess whether there is statistical evidence that the related populationmeans are…

Q: (c) Find the 20 th percentile of the sample mean.

A: (c) Given that, The 20th percentile of sample mean is,

Q: you want to obtain a sample to estimate a population mean. based on previous evidence, you believe…

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Q: Continuing the last question: An accountant wants to know the mean time to prepare a tax return.…

A: Given,sample size(n)=20sample mean(x¯)=2.67standard deviation(s)=0.95degrees of…

Q: How much more likely are college men than college women to participate in intramural sports?  A…

A: Given information: Number of college men surveyed, n1=688 Number of college women surveyed, n2=579…

Q: You collect a sample of 69 observations of animal heights, in mm. The sample mean is 41.89 and the…

A: Given: x¯=41.89s=4.33n=69 The degrees of freedom is obtained as below: df=n-1=69-1=68 The critical…

Q: Use the confidence interval to find the margin of error and the sample mean. (0.278,0.400) The…

A: We have given the confidence interval(0.278, 0.400)Lower limit = 0.278Upper limit = 0.400

Q: You are given the sample mean and the population standard deviation. Use this information to…

A: n=47, sample mean =111.62, standard deviations=11.42

Q: Suppose you survey a random sample from a large population to understand the population proportion.…

A: Given information- Margin of error, E = 6% = 0.06 Confidence level, c = 98% Since nothing is known…

Q: Assume that population mean is to be estimated from the sample described. Use the sample results to…

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Q: You want to create a Z-interval for a population mean, using table C, with the following…

A: From the provided information, Sample size (n) = 25 Mean (x̅) = 34.2 Population standard deviation…

Q: A student did a poll of a sample of 32 students at Ooltewah and found their amount of pets they…

A: Given that  The data is normally distributed. Sample size (n) = 32 Sample mean (x¯) = 3.4 Population…

Q: You would like to construct a 99% confidence interval to estimate the population mean score on a…

A: Solution: Let X be the score. From the given information, x-bar=485 and S=70. Here, it needed to…

Q: Find the critical value that corresponds to 95% confidence for a mean and n = 35.

A: Given that - Find the critical value that corresponds to 95% confidence for a mean and n = 35.

Q: You are testing the difference between a sample mean and a population mean in a one-tailed test that…

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Q: 90% confidence

A: n = 130  x= 69  p'=xn=0.5307 p=p' ±Zαp'(1-p')n =0.5307±1.645*0.04377=0.5307±0.07200=(0.458,0.6027)

Q: You have 16 vampire bats. These bats have a population variance of 3.4 ounces. You wish to make a…

A: Given: Sample size (n) = 16 Population variance σ2=3.4 Sample mean x¯=15.20 Confidence level = 0.950

Q: Suppose you survey a random sample from a large population to understand the population proportion.…

A: Obtain the sample size of a no preliminary estimate for p. The formula of sample size is, Obtain…

Q: Determine the margin of error. It has been determined with 95% confidence that the proportion of…

A: Given: 95% confidence interval is (0.78, 0.82) So, Lower limit = 0.78 Upper limit = 0.82

Q: You intend to estimate a population mean with a confidence interval. You believe the population to…

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Q: You plan to build a 95% confidence interval estimate of the mean of a large population. You want a…

A: Givenconfidence level=95%Margin of error(E)=10standard deviation(σ)=200

Q: magine that you conduct a study and estimate that the prevalence of hypertension among employees of…

A: From the provided information, Sample proportion (p̂) = 0.24 Margin of error for a 95% confidence…

Q: n= 1655 (nubers of tries), x=176 (number of success tries), 98% confidence. Find the confidence…

A: We have given that  Sample size=n=1655 Favorable=X=176 98% confidence

Q: How do you tell if a ANOVA is significant given the F value, p value, and eta squared? What does the…

A: In ANOVA, the null hypothesis is that there is no difference between group methods. If any group…

Q: Please solve step 2,3,4 …thank you!

A: Given Information: The hypothesized value for the 2013 average annual number of Melanoma, mortality…

Q: What is the multiplier for an interval that estimates the proportion with  a. 88% confidence?  b.…

A: Confidence Interval: The form of the confidence interval is, CI = Point estimate ± Margin of error…

Q: Assume that population mean is to be estimated from the sample described. Use the sample results to…

A: Given information Sample size (n) = 49 Sample mean x̅ = 55.1 Standard deviation (s) = 4.8…