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Please refer to part (a) of Figure 1. Here, alpha (the angle at the top of the triangular prism) is 66.3 degrees. What is theta (the angle below the horizontal that the ray makes emerging from the prism on the right)?

		46.0 degrees
		32.2 degrees
		59.8 degrees
		82.8 degrees

(a)
(b)
(c)
Air, n, = 1
H,0
n, = 1.33
Input ray, parallel
air
%3D
to
base
glass
nz = 1.5
10m
Input ray,
horizontal
Glass, n2 = 1.5
H20
glass n2 = 1.5

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