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What is the y-intercept for this equation? f (x) = -3a2 - 4x + 7

What is the y-intercept for this equation? f (x) = -3a2 - 4x + 7

Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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**Question:** What is the y-intercept for this equation? \( f(x) = -3x^2 - 4x + 7 \) **Explanation:** To find the y-intercept of a quadratic equation in the form \( f(x) = ax^2 + bx + c \), you set \( x = 0 \) and solve for \( f(x) \). In this equation, the y-intercept is the constant term, which is \( c = 7 \). Therefore, the y-intercept of the equation \( f(x) = -3x^2 - 4x + 7 \) is at the point (0, 7). This means that the graph of the equation will cross the y-axis at 7.
Transcribed Image Text:**Question:** What is the y-intercept for this equation? \( f(x) = -3x^2 - 4x + 7 \) **Explanation:** To find the y-intercept of a quadratic equation in the form \( f(x) = ax^2 + bx + c \), you set \( x = 0 \) and solve for \( f(x) \). In this equation, the y-intercept is the constant term, which is \( c = 7 \). Therefore, the y-intercept of the equation \( f(x) = -3x^2 - 4x + 7 \) is at the point (0, 7). This means that the graph of the equation will cross the y-axis at 7.
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