**Question:**What is the volume when 3.20 kg of copper wires are melted, then cooled into a solid cube?\[ \text{The density of copper wires is 8.96 g/cm}^3 \]\[ \_\_\_\_ \text{ cm}^3 \]**Explanation:**To find the volume of the copper cube, we need to use the relationship between mass, volume, and density, which is given by the formula:\[ \text{Density} (\rho) = \frac{\text{Mass} (m)}{\text{Volume} (V)} \]Rearranging the formula to solve for volume:\[ \text{Volume} (V) = \frac{\text{Mass} (m)}{\text{Density} (\rho)} \]Given:- Mass, \( m = 3.20 \text{ kg} = 3200 \text{ g} \) (since \( 1 \text{ kg} = 1000 \text{ g} \))- Density, \( \rho = 8.96 \text{ g/cm}^3 \)Substitute the values into the formula:\[ V = \frac{3200 \text{ g}}{8.96 \text{ g/cm}^3} \]\[ V = 357.14 \text{ cm}^3 \]Therefore, the volume of the copper cube when the 3.20 kg of copper wires are melted and then cooled into a solid cube is approximately 357.14 cm³.

Given that: Mass of copper wires m = 3.2 kg = 3200 g Density of copper wire ρ = 8.96 g/cm3 Let…

Answered: What is the volume when 3.20 kg of…

What is the volume when 3.20 kg of copper wires are melted, then cooled into a solid cube? [the density of copper wires is 8.96 g/cm³]

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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