What is the volume of the sphere in the figure shown below? 2.6 m

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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What is the volume of the sphere in the figure shown below?

The image displays a set of four multiple-choice options, each accompanied by a circular button for selection. These options represent different measurements in cubic meters (m³):

1. \( \bigcirc \) 11.2 m³
2. \( \bigcirc \) 2.9 m³
3. \( \bigcirc \) 27.6 m³
4. \( \bigcirc \) 9.2 m³

There are no graphs or diagrams associated with this text, only the listed numerical options.
Transcribed Image Text:The image displays a set of four multiple-choice options, each accompanied by a circular button for selection. These options represent different measurements in cubic meters (m³): 1. \( \bigcirc \) 11.2 m³ 2. \( \bigcirc \) 2.9 m³ 3. \( \bigcirc \) 27.6 m³ 4. \( \bigcirc \) 9.2 m³ There are no graphs or diagrams associated with this text, only the listed numerical options.
**Problem Statement:**

What is the volume of the sphere in the figure shown below?

**Diagram Explanation:**

The image shows a green sphere with a dotted line across its diameter, which is labeled as 2.6 meters.

To find the volume of the sphere, use the formula for the volume of a sphere:

\[ V = \frac{4}{3} \pi r^3 \]

Where \( r \) is the radius of the sphere. In this case, the diameter is given as 2.6 meters, so the radius \( r \) is half of that:

\[ r = \frac{2.6}{2} = 1.3 \text{ meters} \]

Thus, the volume \( V \) can be calculated as:

\[ V = \frac{4}{3} \pi (1.3)^3 \]
Transcribed Image Text:**Problem Statement:** What is the volume of the sphere in the figure shown below? **Diagram Explanation:** The image shows a green sphere with a dotted line across its diameter, which is labeled as 2.6 meters. To find the volume of the sphere, use the formula for the volume of a sphere: \[ V = \frac{4}{3} \pi r^3 \] Where \( r \) is the radius of the sphere. In this case, the diameter is given as 2.6 meters, so the radius \( r \) is half of that: \[ r = \frac{2.6}{2} = 1.3 \text{ meters} \] Thus, the volume \( V \) can be calculated as: \[ V = \frac{4}{3} \pi (1.3)^3 \]
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