What is the volume of a right circular cylinder with its base's diameter of 16.22 and height of 14.98? Use л = 3.14 as needed. Round to two decimal places as needed.
What is the volume of a right circular cylinder with its base's diameter of 16.22 and height of 14.98? Use л = 3.14 as needed. Round to two decimal places as needed.
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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![**Problem Statement:**
What is the volume of a right circular cylinder with its base's diameter of 16.22 and height of 14.98?
**Instructions:**
Use π = 3.14 as needed. Round to two decimal places as needed.
---
To find the volume of a right circular cylinder, you can use the formula:
\[ V = \pi r^2 h \]
where:
- \( V \) is the volume,
- \( r \) is the radius of the cylinder's base,
- \( h \) is the height of the cylinder.
Given:
- Diameter of the base \( d = 16.22 \)
- Height \( h = 14.98 \)
- \( \pi = 3.14 \)
First, calculate the radius \( r \) of the base:
\[ r = \frac{d}{2} = \frac{16.22}{2} = 8.11 \]
Next, substitute the values into the volume formula:
\[ V = 3.14 \times (8.11)^2 \times 14.98 \]
Perform the calculation:
\[ V = 3.14 \times 65.8121 \times 14.98 \]
\[ V ≈ 3.14 \times 985.37 \]
\[ V ≈ 3094.97 \]
Thus, the volume of the cylinder is approximately \( 3094.97 \) cubic units, rounded to two decimal places.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F91652952-972c-437d-817e-6a9e046f1c10%2Fb4cc4813-7b8c-4b84-8e7d-7a474bd1828e%2Fz1y89o_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
What is the volume of a right circular cylinder with its base's diameter of 16.22 and height of 14.98?
**Instructions:**
Use π = 3.14 as needed. Round to two decimal places as needed.
---
To find the volume of a right circular cylinder, you can use the formula:
\[ V = \pi r^2 h \]
where:
- \( V \) is the volume,
- \( r \) is the radius of the cylinder's base,
- \( h \) is the height of the cylinder.
Given:
- Diameter of the base \( d = 16.22 \)
- Height \( h = 14.98 \)
- \( \pi = 3.14 \)
First, calculate the radius \( r \) of the base:
\[ r = \frac{d}{2} = \frac{16.22}{2} = 8.11 \]
Next, substitute the values into the volume formula:
\[ V = 3.14 \times (8.11)^2 \times 14.98 \]
Perform the calculation:
\[ V = 3.14 \times 65.8121 \times 14.98 \]
\[ V ≈ 3.14 \times 985.37 \]
\[ V ≈ 3094.97 \]
Thus, the volume of the cylinder is approximately \( 3094.97 \) cubic units, rounded to two decimal places.
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