What is the vertex (are the vertices) of the shapeformed by the equation(y+5)²25= 1?O (7,5)O (7,0) and (-7, 0)O (10,-5) and (-4,-5)O (0,5) and (0, -5)O (3,0) and (3, -10)(x-3)²49

Answered: Image /qna-images/answer/de6b5035-724d-41ad-841c-adc8584459e3.jpg

Answered: What is the vertex (are the vertices)…

What is the vertex (are the vertices) of the shape formed by the equation (x-3)² (3+5)² = 1? 49 25 O (7,5) O (7,0) and (-7, 0) O (10,-5) and (-4,-5) O (0,5) and (0, -5) O (3,0) and (3,-10)

Algebra and Trigonometry (6th Edition)

6th Edition

ISBN:9780134463216

Author:Robert F. Blitzer

Publisher:Robert F. Blitzer

ChapterP: Prerequisites: Fundamental Concepts Of Algebra

Section: Chapter Questions

Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...

See similar textbooks

Similar questions

23. Simplify the complex fraction 1 stamen 2x+3 2x x+3 x + 2x+3 2x+3 O x+3 1 x+3
B) (x + 10) +y-10)"= 16
Find the number of 5-tuples (a, b, c, d, e) of positive odd integers that are solutions to the equation a+b+c+ d +e = 65.
(3 r+1)^{-2 / 3}+(3 r+1)^{1 / 3}+(3 r+1)^{4 / 3}
x² -14x+54 =0 37. Complete the square and rewrite the equation as the square of a binomial. A) (x-7)' =-5 B) (x-7) =-40 C) (x-7)° =- D) (x-7) =5 =-49 38. Solve by using the Square Root Property. A) x=7-7i,7+7i B) x=7-i5,7+i/5 C) x=7-5,7+V5 D) x=7-2i/10,7+2i/10 x' +6x =-6 39. Complete the square and rewrite the equation as the square of a binomial. A) (x+3) =9 B) (x+3)' =0 C) (x+3)* =: D) (x+3)' = 3 40. Solve by using the Square Root Property. A) x =-3-5,-3+v15 B) x = 0,6 C) x =-3 D) x=-3-3,-3+ V3
((1/z-6)-(1/z+6))/(12/z^2-36)
O 1. What Is the difference of +7z+12 72+30z (2+3)(z-3)(z+4) 2"7-3, x3, x -4 1la+42x (2+3)(z–3)(=+4) » " -3, a3, a -4 72 (z+3)(2-3)(z+4) ,*# -3, a # 3, æ -4 72+422 (2+3)(z-3)(z+4) 2-3, a 3, a 7 -4
(5х + 1)х + 3)2 y = (x4 + 6)(x + S)
5. Factor the binomial: 125z°yz +27. O (5z'yz- 3) (25z - 15a'yz+9) O (5a'yz+3)(252®y* - 15a'yz+9) O (5'yz – 3) (252°y+ 15a*y z+9) | O (5z"yz + 3) (25x®y2 + 15a'yz+ 9)
3 The roots of the equation x-4x +9 -0 are 2) 2+ /5 3) 2+1/13 4) 2 13