What is the value of A after 3 iterations of the main for-loop?
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
Related questions
Question
Q5 correct answer
![Algorithm findSmallest(A|i.. n) returns the index of the smallest value in
A[i. .n].
O1, 3, 8, 5, 2, 7, 6, 4
O1, 2, 3, 4, 8, 7,6, 5
O1, 2, 3, 5, 8, 7, 6, 4
O1, 2, 3, 4, 5, 6, 7, 8
O1, 3, 5, 8, 2, 7, 6, 4
O1, 2, 8, 5, 3, 7, 6, 4
O None of these
O1, 2, 3, 5, 8, 7, 6, 4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F778d76aa-1d5b-48ac-99fc-b22d9e954451%2F8fe1ce2e-5840-40e0-9000-fd69a0f6d6ac%2Fl5tg3rr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Algorithm findSmallest(A|i.. n) returns the index of the smallest value in
A[i. .n].
O1, 3, 8, 5, 2, 7, 6, 4
O1, 2, 3, 4, 8, 7,6, 5
O1, 2, 3, 5, 8, 7, 6, 4
O1, 2, 3, 4, 5, 6, 7, 8
O1, 3, 5, 8, 2, 7, 6, 4
O1, 2, 8, 5, 3, 7, 6, 4
O None of these
O1, 2, 3, 5, 8, 7, 6, 4
![Question 5
Consider the Selection Sort algorithm we saw in class on the following input array
A:
8, 3, 1, 5, 2, 7, 6, 4
What is the value of A after 3 iterations of the main for-loop?
Algorithm SelectionSort(A[1..n)
For i :=1 ton – 1
k := findSmallest(A[i..n])
swap A[i] and A[k
-
End-for
Algorithm findSmallest(A|i.. n) returns the index of the smallest value in
A[2. . n].
O1, 3, 8, 5, 2, 7, 6, 4
O1, 2, 3, 4, 8, 7, 6, 5](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F778d76aa-1d5b-48ac-99fc-b22d9e954451%2F8fe1ce2e-5840-40e0-9000-fd69a0f6d6ac%2Fc6khzm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Question 5
Consider the Selection Sort algorithm we saw in class on the following input array
A:
8, 3, 1, 5, 2, 7, 6, 4
What is the value of A after 3 iterations of the main for-loop?
Algorithm SelectionSort(A[1..n)
For i :=1 ton – 1
k := findSmallest(A[i..n])
swap A[i] and A[k
-
End-for
Algorithm findSmallest(A|i.. n) returns the index of the smallest value in
A[2. . n].
O1, 3, 8, 5, 2, 7, 6, 4
O1, 2, 3, 4, 8, 7, 6, 5
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