College Physics
10th Edition
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter9: Solids And Fluids
Section: Chapter Questions
Problem 77AP: An iron block of volume 0.20 m5 is suspended from a spring scale and immersed in a flask of water....
Related questions
Question
![**Problem Statement:**
A wooden crate has a mass of 2 kg and it is floating halfway submerged in water. What is the upward buoyant force exerted by water \(1000 \, \text{kg/m}^3\) on the crate?
**Explanation:**
To solve this problem, we need to apply Archimedes' principle, which states that the buoyant force on a submerged object is equal to the weight of the fluid displaced by the object.
**Key Details:**
1. **Mass of the Crate:**
- The crate's mass is 2 kg.
2. **Density of Water:**
- The density of water is \(1000 \, \text{kg/m}^3\).
3. **Submersion Level:**
- The crate is floating halfway submerged.
**Solution Steps:**
- The weight of the crate (\(W\)) is given by:
\[
W = \text{mass} \times \text{gravity} = 2 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 19.6 \, \text{N}
\]
- Because the crate is floating, the upward buoyant force (\(F_b\)) must be equal to the weight of the crate:
\[
F_b = 19.6 \, \text{N}
\]
Thus, the upward buoyant force exerted by the water on the crate is \(19.6 \, \text{N}\).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F805df41e-b889-4c16-a267-318b4eb3cf21%2F9034f87c-b6fa-4bd9-86c1-ca1d2d4896a9%2Fbfnk687_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
A wooden crate has a mass of 2 kg and it is floating halfway submerged in water. What is the upward buoyant force exerted by water \(1000 \, \text{kg/m}^3\) on the crate?
**Explanation:**
To solve this problem, we need to apply Archimedes' principle, which states that the buoyant force on a submerged object is equal to the weight of the fluid displaced by the object.
**Key Details:**
1. **Mass of the Crate:**
- The crate's mass is 2 kg.
2. **Density of Water:**
- The density of water is \(1000 \, \text{kg/m}^3\).
3. **Submersion Level:**
- The crate is floating halfway submerged.
**Solution Steps:**
- The weight of the crate (\(W\)) is given by:
\[
W = \text{mass} \times \text{gravity} = 2 \, \text{kg} \times 9.8 \, \text{m/s}^2 = 19.6 \, \text{N}
\]
- Because the crate is floating, the upward buoyant force (\(F_b\)) must be equal to the weight of the crate:
\[
F_b = 19.6 \, \text{N}
\]
Thus, the upward buoyant force exerted by the water on the crate is \(19.6 \, \text{N}\).
Expert Solution

Step 1
Given:
Mass of the wooden crate=2 kg
Let density of wood crate be Dwc=600 kg/cm3
Density of Water Dw=1000Kg/cm3
To Find:
Buoyant Force Fb=?
Step by step
Solved in 2 steps

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