What is the total current of the load schedule? Use A as the unit.

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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What is the total current of the load schedule? Use A as the unit.

For feeder conductor, choose the correct answer.
22
24
25
40
73.79
79.73
1.25(answer
in previous
question) is
equal to:
Use 2-[?]
sqmm THW
Cu wire.
and [?] mm-
diameter PVC
pipe
Transcribed Image Text:For feeder conductor, choose the correct answer. 22 24 25 40 73.79 79.73 1.25(answer in previous question) is equal to: Use 2-[?] sqmm THW Cu wire. and [?] mm- diameter PVC pipe
Use the table below. Write your answers on the space provided after the table.
Write only the numerical value for the 10 missing items on the table.
CKT NO. LOAD DESCRIPTION
VOLTAGE TOTAL VA AMP/CKT AT AF SQMM TYPE MM (DIA) TYPE
1
9 Ligthing Outlets
230
900
[1]
15 50
2.0
THW
15
PVC
2
7 Lighting Outlets
230
[2]
[3]
15 50
2.0
THW
15
PVC
3
7 Lighting Outlets
230
700
[4]
|15 50
2.0
THW
15
PVC
9 Convenience Outlets
230
[5]
[6]
20 50
3.5
THW
15
PVC
5
Refrigerator
230
1840
8.0
20 50
3.5
THW
15
PVC
6
ACU, 1.5 HP
230
[7]
[8]
20 50
3.5
THW
15
PVC
7
ACU, 2.0 HP
230
[9]
[10]
20 50
3.5
THW
15
PVC
8
SPARE
230
2760
12.0
20 50
3.5
THW
15
PVC
4)
Transcribed Image Text:Use the table below. Write your answers on the space provided after the table. Write only the numerical value for the 10 missing items on the table. CKT NO. LOAD DESCRIPTION VOLTAGE TOTAL VA AMP/CKT AT AF SQMM TYPE MM (DIA) TYPE 1 9 Ligthing Outlets 230 900 [1] 15 50 2.0 THW 15 PVC 2 7 Lighting Outlets 230 [2] [3] 15 50 2.0 THW 15 PVC 3 7 Lighting Outlets 230 700 [4] |15 50 2.0 THW 15 PVC 9 Convenience Outlets 230 [5] [6] 20 50 3.5 THW 15 PVC 5 Refrigerator 230 1840 8.0 20 50 3.5 THW 15 PVC 6 ACU, 1.5 HP 230 [7] [8] 20 50 3.5 THW 15 PVC 7 ACU, 2.0 HP 230 [9] [10] 20 50 3.5 THW 15 PVC 8 SPARE 230 2760 12.0 20 50 3.5 THW 15 PVC 4)
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