What is the time complexity of the Dynamic Programming Algorithm in the last example of the relevant slides ? Give an asymptotically tight bound (Θ(?)). Prove your answer.

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PLEASE PROVE IN ACADEMIC WAY

What is the time complexity of the Dynamic Programming Algorithm in the last example of the relevant slides ? Give an asymptotically tight bound (Θ(?)). Prove your answer.

Solution
• For 1 <isj< n, we let T[i,j] C {a, b, c} denote the set of symbols e for which
there is a parenthesization of x;..X; yielding e. We let e ® b denote the product
of e and b using the table. p e {a, b, c} is the symbol we are considering.
• Pseudocode
for i +1 to n do
T[i, i] + X;
for s +1 to n-1 do
for i +1 to n-s do
T[i,i + s] + Ø
for k +i to i+s-1 do
for each e e T[i,k] do
for each b e T[k + 1,i + s] do
T[i,i+s] + T[i,i+s] Ue ® b
if p e T[1,n] then
return yes
else
return no
Transcribed Image Text:Solution • For 1 <isj< n, we let T[i,j] C {a, b, c} denote the set of symbols e for which there is a parenthesization of x;..X; yielding e. We let e ® b denote the product of e and b using the table. p e {a, b, c} is the symbol we are considering. • Pseudocode for i +1 to n do T[i, i] + X; for s +1 to n-1 do for i +1 to n-s do T[i,i + s] + Ø for k +i to i+s-1 do for each e e T[i,k] do for each b e T[k + 1,i + s] do T[i,i+s] + T[i,i+s] Ue ® b if p e T[1,n] then return yes else return no
• Let us define a binary operation ® on three symbols a, b, c according
to the following table; thus a b = b , b® a = c , and so on. Notice
that the operation defined by the table is neither associative nor
commutative.
a
b
C
a
b
a
a
Describe an efficient algorithm that examines a string of these
symbols, say bbbbac , and decides whether or not it is possible to
parenthesize the string in such a way that the value of the resulting
expression is p = a. For example, on input bbbbac your algorithm
should return yes because ((b® (b® b)) ® (b ® a)) ® c = a.
Transcribed Image Text:• Let us define a binary operation ® on three symbols a, b, c according to the following table; thus a b = b , b® a = c , and so on. Notice that the operation defined by the table is neither associative nor commutative. a b C a b a a Describe an efficient algorithm that examines a string of these symbols, say bbbbac , and decides whether or not it is possible to parenthesize the string in such a way that the value of the resulting expression is p = a. For example, on input bbbbac your algorithm should return yes because ((b® (b® b)) ® (b ® a)) ® c = a.
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