What is the time complexity and Big O notation for each of the following code segments? for(i=0;i
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What is the time complexity and Big O notation for each of the following code segments?
for(i=0;i<n; i++)
{
for(j=0;j<n;j*2)
{
Statement;
}
}
f(n) =
O(n) =
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- 11 - The code segment below has time complexity? for (int i=0; isum = 0; for (int i = 1; i< n; i = sum++ || 2*i)Q5. Find the time complexity of the following code int b = 0; for (j = 0; jj; i--) { b=b+j+i;In questions 4-10 estimate the Big O value by analyzing the code. Note the algorithms are written in English. Hint: you are interested in the number of operations for each algorithm.In questions 4-10 estimate the Big O value by analyzing the code. Note the algorithms are written in English. Hint: you are interested in the number of operations for each algorithm.Following C code computes the approximate roots and the absolute approximate error of f(x)=x³ -(1/sin(x)) function with both Regula-Falsi and Bisection methods for ten iterations. If the user enters key "1" Regula-Falsi method, if the user enters key "2" Bisection method, will run in the program. In this context, fill in the blanks of the given C code. double function(double x) { return int main(int argc, char *argv[]) { double a,b,x[10],error,FA,FB,FX; int option,i; printf(" ENTER 1 FOR Regula Falsi, ITER Bisection \n"); scanf("%d",&option); printf("Enter base of definition invterval\n"); scanf("%lf",&a); printf("Enter top of definition interval\n"); scanf("%lf",&b); FA= function (a); FB= function (b); if(FA*FB<0){ for(i=0;i< ;i++){ switch(option){ case 1: break;Figure 2 void sort_Algo (int anArray[], int n) { int i, j, idx; for (i = 0; i anArray[ idx ]) idx = j; Swap (anArray[ idx ], anArray[ i ]); } } int main() { const int n = 8; int anArray[n] { -9, 14, 52, 106, 22, -1, 99}; sort_Algo(anArray, n); } Name the sorting algorithm exercised by the sort_Algo() function. * Your answer Determine if anArray[] is to be sorted into ascending, or descending order. Your answer Trace the sorting algorithm in Figure 2 as it sorts anArray[]. (Answer the question according to the format, eg. Pass 0:3, 3, 3; Pass 1: 3, 3, 3; Pass2: 3, 3, 3;) * Your answerCode: #include <bits/stdc++.h> using namespace std; void BUBBLE(int A[],int N){ for(int k=0;k<N-1;++k){ for(int ptr=0;ptr<N-k-1;++ptr){ if(A[ptr]>A[ptr+1]){ int temp = A[ptr]; A[ptr] = A[ptr+1]; A[ptr+1]=temp; } } }} //function to print the arrayvoid printArray(int arr[],int n){ int i; for(i=0;i<n;i++) cout<<arr[i]<<" "; cout<<endl;} //driver function to test the modulesint main(){ int arr[] ={15,17,5,3,25,66,14,7,59,100}; int n=sizeof(arr)/sizeof(arr[0]); cout<<"\nOriginal array: "; printArray(arr,n); cout<<"\n\nOutput of Bubble sort are shown below:\n"; BUBBLE(arr,n); printArray(arr, n); return 0;} Q: Remove the Function from the above code#include<bits/stdc++.h> using namespace std; void bubbleSort(int arr[], int n) { for (int i = 0; i < n - 1; i++) { for (int j = 0; j < n - i - 1; j++) { if (arr[j] > arr[j + 1]) { int temp = arr[j]; arr[j] = arr[j + 1]; arr[j + 1] = temp; } } } } int binarySearch(int arr[], int l, int r, int x, int& comp) { comp++; if (r >= l) { int mid = l + (r - l) / 2; if (arr[mid] == x) { return mid; } if (arr[mid] > x) { return binarySearch(arr, l, mid - 1, x, comp); } return binarySearch(arr, mid + 1, r, x, comp); } return -1; } int main() { int Num[8192]; srand(time(NULL)); for (int i = 0; i < 8192; i++) { Num[i] = rand() % 10001; } clock_t starting_time = clock(); bubbleSort(Num, 8192); clock_t ending_time = clock(); clock_t result =…// 9. Is It Prime? function isPrime(n) { if (n < 2 || n % 1 != 0) { return false; } for (let i if (n % i } return true; 2; i < n; ++i) { 0) return false; == }Instruction: Explain the function of the program line by line thoroughly.Program: #include <iostream>using namespace std; void sort(int a[], int num){ for(int i =0; i < num; i++){ for(int j = i+1; j < num; j++){ if(a[j] < a[i]) a[i] = a[i] + a[j] -(a[j] = a[i]); } }} int main(){ int n; cout<<"Enter number of integers: "; cin >> n; int *a = new int[n]; // Dynamic memory allocation using new. int val; for(int i =0; i < n; i++){ cout << " Enter integer No. "<< i+1 << ": "; cin >> val; a[i] = val; } sort(a,n); cout << "\nSorted Integers: "; for(int i =0; i < n; i++) cout << a[i] << " "; return 0;}include <bits/stdc++.h> using namespace std; int MSD(int n){ if(n == 0) return 0; int k = log10(n); int x = pow(10,k); int ans = n/x; return ans; } int main() { int n; cin >> n; cout << MSD(n).SEE MORE QUESTIONS