What is the theoretical yield of the given reaction? CH2C1, + 6 H* +6 e¯ → CH4(9) + HClg) Given based on the experiment: 6 mL DCM (84.93g/mol), 2.00 mL CUSO. (159.61g/mol) solution, and 5.00 g Zn (65.38g/mol) dust. 6mL x 1.33g/mL = (7.98g x 1mol/84.93g),cm X (16.04g/1mol)CH, = 1.507 g CH, gas

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TOPIC: Preparation of Methane

Expound and explain the solution given.

What is the theoretical yield of the given reaction?
CH,Cl2 + 6 H++ 6 e¯ → CH4(g) + HC\9)
Given based on the experiment: 6 mL DCM (84.93g/mol), 2.00 mL CUSO,
(159.61g/mol) solution, and 5.00 g Zn (65.38g/mol) dust.
6mL x 1.33g/mL = (7.98g x 1mol/84.93g)pCM × (16.04g/1mol)CH, = 1.507 g CH, gas
%3D
%3D
Transcribed Image Text:What is the theoretical yield of the given reaction? CH,Cl2 + 6 H++ 6 e¯ → CH4(g) + HC\9) Given based on the experiment: 6 mL DCM (84.93g/mol), 2.00 mL CUSO, (159.61g/mol) solution, and 5.00 g Zn (65.38g/mol) dust. 6mL x 1.33g/mL = (7.98g x 1mol/84.93g)pCM × (16.04g/1mol)CH, = 1.507 g CH, gas %3D %3D
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