Part CWhat is the tangential speed of a point on the rim of the turntable at t= 0,207 s?Express your answer in meters per second.V=1.11 m/sPrevious AnswersCorrectPart DWhat is the magnitude of the resultant acceleration of a point on the rim at t= 0.207 s?Express your answer in meters per second squared.阳AE4a=7.95m/sSubmitPrevious Anywers Request Answerx Incorrect; Try Again; One attempt remaining An electric turntable 0.740 m in diameter is rotating about a fixed axis with an initial angular velocity of0.290 rev/s and a constant angular acceleration of 0.909 rev/sPart ACompute the angular velocity of the turntable after 0.207 sExpress your answer in revolutions per second.W= 0473 rev/sPrevious AnsWersCorrectPart BThrough how many revolutions has the turntable spun in this time interval?Express your answer in revolutions.N= 795-102 rev

Given data: d=0.74 mωi=0.29 rev/sα=0.909 rev/s2 Need to determine the angular, tangential velocity…

Answered: What is the tangential speed of a point…

What is the tangential speed of a point on the rim of the turntable at t =0,207 s? Express your answer in meters per second. V= 1.11 m/s Previous Anawers v Correct

Elements Of Electromagnetics

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Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

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Concept explainers

Power Transmission Elements

It is defined as the energy transfer from one location to another location. The energy will start moving from the energy generation source to the energy applied position to obtain the work output. From this method, a large amount of electric energy moves from the power station to various electrical substations.

Question

Part C
What is the tangential speed of a point on the rim of the turntable at t= 0,207 s?
Express your answer in meters per second.
V=1.11 m/s
Previous Answers
Correct
Part D
What is the magnitude of the resultant acceleration of a point on the rim at t= 0.207 s?
Express your answer in meters per second squared.
阳AE4
a=7.95
m/s
Submit
Previous Anywers Request Answer
x Incorrect; Try Again; One attempt remaining

An electric turntable 0.740 m in diameter is rotating about a fixed axis with an initial angular velocity of
0.290 rev/s and a constant angular acceleration of 0.909 rev/s
Part A
Compute the angular velocity of the turntable after 0.207 s
Express your answer in revolutions per second.
W= 0473 rev/s
Previous AnsWers
Correct
Part B
Through how many revolutions has the turntable spun in this time interval?
Express your answer in revolutions.
N= 795-102 rev

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