**Problem:**What is the strength of the magnetic field produced at the center of the solenoid of length 24 cm and 450 turns? The current in the solenoid is 4.0 A. (\( \mu_0 = 4\pi \times 10^{-7} \, \text{T} \cdot \text{m/A} \))**Options:**- ○ 4.8 mT- ○ 9.4 mT- ○ 0.20 T- ○ 0.0063 T- ○ 3.2 mT**Explanation:**To solve this problem, use the formula for the magnetic field inside a solenoid:\[ B = \mu_0 \cdot \left(\frac{N}{L}\right) \cdot I \]Where:- \( B \) is the magnetic field,- \( \mu_0 \) is the permeability of free space,- \( N \) is the number of turns,- \( L \) is the length of the solenoid,- \( I \) is the current.**Calculation Steps:**1. Convert the length of the solenoid from centimeters to meters: \( L = 24 \, \text{cm} = 0.24 \, \text{m} \).2. Use the formula to calculate \( B \).This question is part of a physics-based educational problem set that helps understand the properties of magnetic fields in solenoids.

Answered: Image /qna-images/answer/548d7118-d0d7-4260-819f-62b030c92160.jpg

What is the strength of the magnetic field produced at the center of the solenoid of length 24 cm and 450 turns. The current in the solenoid is 4.0 A. (μo = 4 x 10-7 T.m/A) 4.8 mT 9.4 m T 0.20 T 0.0063 T 3.2 mT

What is the strength of the magnetic field produced at the center of the solenoid of length 24 cm and 450 turns. The current in the solenoid is 4.0 A. (μo = 4 x 10-7 T.m/A) 4.8 mT 9.4 m T 0.20 T 0.0063 T 3.2 mT

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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