Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
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Can u help me with these two?
![**Determining the Standard Equation of a Circle**
When provided with the center and radius of a circle, the standard equation of the circle can be derived using the formula:
\[ (x - h)^2 + (y - k)^2 = r^2 \]
where \((h, k)\) represents the center of the circle and \(r\) represents the radius.
**Examples:**
1. **Problem 9:**
- **Given:** Center = \((2, 3)\); Radius = \(5\)
- **Solution:** Substituting the given values into the standard equation formula:
\[
(x - 2)^2 + (y - 3)^2 = 5^2
\]
This simplifies to:
\[
(x - 2)^2 + (y - 3)^2 = 25
\]
2. **Problem 10:**
- **Given:** Center = \((0, -1)\); Radius = \(\sqrt{7}\)
- **Solution:** Substituting the given values into the standard equation formula:
\[
(x - 0)^2 + (y + 1)^2 = (\sqrt{7})^2
\]
This simplifies to:
\[
x^2 + (y + 1)^2 = 7
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Transcribed Image Text:**Determining the Standard Equation of a Circle**
When provided with the center and radius of a circle, the standard equation of the circle can be derived using the formula:
\[ (x - h)^2 + (y - k)^2 = r^2 \]
where \((h, k)\) represents the center of the circle and \(r\) represents the radius.
**Examples:**
1. **Problem 9:**
- **Given:** Center = \((2, 3)\); Radius = \(5\)
- **Solution:** Substituting the given values into the standard equation formula:
\[
(x - 2)^2 + (y - 3)^2 = 5^2
\]
This simplifies to:
\[
(x - 2)^2 + (y - 3)^2 = 25
\]
2. **Problem 10:**
- **Given:** Center = \((0, -1)\); Radius = \(\sqrt{7}\)
- **Solution:** Substituting the given values into the standard equation formula:
\[
(x - 0)^2 + (y + 1)^2 = (\sqrt{7})^2
\]
This simplifies to:
\[
x^2 + (y + 1)^2 = 7
\]
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