QUESTION 5What is the standard enthalpy of formation of liquid methanol, CH3OH()?C(graphite) + O2(g) - CO2(g)AH°TXN = -393.5 kJ/molH2(g) + ½O2- H20(1)AH°rxn = -285.8 kJ/molCH3OH() + 3/202(9) → CO2(g) + 2H20()AHrxn = -726.4 kJ/molO -238.7 kJ/molO -1691.5 kJ/molO -47.1 kJ/molO 47.1 kJ/molO 1691.5 kJ/molQUESTION 6Benzene is a starting material in the synthesis of nylon fibers and polystyrene (styrofoam). Its specific heat capacity is 1.74 J/g.°C. If 16.7 kJ of energy is absorbed by a 225-g sample ofbenzene at 20.0°C, what is its final temperature?О 37.7°СО 80.1°CO 42.7°CО 62.7°СО -22.7°С

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What is the standard enthalpy of formation of liquid methanol, CH3OH()? C(graphite) + O2(9) – CO2(9) AH, °rxn = -393.5 kJ/mol H2(g) + ½O2→ H20() AH°rxn = -285.8 kJ/mol CH3OH() + 3/202(g) → CO2(g) + 2H20() AH°rxn = -726.4 kJ/mol -238.7 kJ/mol -1691.5 kJ/mol -47.1 kJ/mol O 47.1 kJ/mol 1691.5 kJ/mol

What is the standard enthalpy of formation of liquid methanol, CH3OH()? C(graphite) + O2(9) – CO2(9) AH, °rxn = -393.5 kJ/mol H2(g) + ½O2→ H20() AH°rxn = -285.8 kJ/mol CH3OH() + 3/202(g) → CO2(g) + 2H20() AH°rxn = -726.4 kJ/mol -238.7 kJ/mol -1691.5 kJ/mol -47.1 kJ/mol O 47.1 kJ/mol 1691.5 kJ/mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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