What is the standard deviation (in milliliters)? 8.3166 x milliliters What is the z value corresponding to 495 milliliters? ==-0.64209 Referring to this table, determine the A value. -4 = 0.2389
What is the standard deviation (in milliliters)? 8.3166 x milliliters What is the z value corresponding to 495 milliliters? ==-0.64209 Referring to this table, determine the A value. -4 = 0.2389
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Question
![As an engineer working for a water bottling company, you collect the following data in order to test the performance of the bottling systems. Assume the normal distribution.
-including answers submitted in WebAssign.)
Milliliters of Water in the Bottle
485
490
495
500
505
510
515
What is the mean (in milliliters)?
500
milliliters
What is the standard deviation (in milliliters)?
8.3166
X milliliters
Frequency
What is the z value corresponding to 495 milliliters?
z = -0.64209
x
Referring to this table, determine the A value.
A = 0.2389
x
8
12
22
35
20
13
12
Determine the probability that a bottle would be filled with more than 495 milliliters.
probability=0.7389
✓](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd261088c-f753-45e4-ae14-7adbaf3c257c%2Ff9451358-5c79-498f-b13a-21822639c32e%2Fich6syk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:As an engineer working for a water bottling company, you collect the following data in order to test the performance of the bottling systems. Assume the normal distribution.
-including answers submitted in WebAssign.)
Milliliters of Water in the Bottle
485
490
495
500
505
510
515
What is the mean (in milliliters)?
500
milliliters
What is the standard deviation (in milliliters)?
8.3166
X milliliters
Frequency
What is the z value corresponding to 495 milliliters?
z = -0.64209
x
Referring to this table, determine the A value.
A = 0.2389
x
8
12
22
35
20
13
12
Determine the probability that a bottle would be filled with more than 495 milliliters.
probability=0.7389
✓
![Milliliters of
Water in
the bottle Frequency x*f
Refer to
tables in
problem
examples
for A #'s
485
490
495
500
505
510
515
485
490
495
Mean
Z
500
505
510
515
Az1
Milliliters of Water in the
bottle
Refer to tables in
problem examples for A
#'s
change first number in z formula
to match what z score is asking for
00 223 22
8
8
12
22
35
12
Frequency
35
20
13
12
20
13
(Mean)
12
Mean
z
A₂1
x-xbar (x-xbar)²+f
3880
500.34 -15.34 1882.9863
5880
500.34 -10.34 1283.4539
10890
500.34
17500 500.34
10100
500.34
6630
500.34
6180 500.34
500.34
-0.64209
0.2389
0.7389
xbar
(Mean) x f
=A77 877
=A78 878
=A79*B79
=A80*880
=A81*B81
=A82 882
=A83*B83
0.2389
-0.5+C87
-5.34 627.78508
-0.34 4.0908759
4.66 433.96157
standard
deviation
9.66 1212.6306
14.66 2578.3257
500.34188034188
-(495-500.34)/F85
change first number in z formula to match what z score is asking for
8.3166
xbar
x-xbar
-SUM(C$3:C$9)/117 =A77-D77
=SUM(C$3:C$9)/117 =A78-D78
=SUM(C$3:C$9)/117 =A79-D79
-SUM(C$3:C$9)/117 A80-D80
-SUM(C$3:C$9)/117 =A81-D81
-SUM(C$3:C$9)/117 A82-D82
-SUM(C$3:C$9)/117 =A83-D83
Answers
(x-xbar) f
=E77^2*877
=E78^2*878
=E79^2*879
=E80^2 880
=E81^2*881
=E82^2*882
=E83^2*883
standard deviation -SQRT(SUM(F77:F83)/(117-1)
Formulas put in](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd261088c-f753-45e4-ae14-7adbaf3c257c%2Ff9451358-5c79-498f-b13a-21822639c32e%2Fgguwm1_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Milliliters of
Water in
the bottle Frequency x*f
Refer to
tables in
problem
examples
for A #'s
485
490
495
500
505
510
515
485
490
495
Mean
Z
500
505
510
515
Az1
Milliliters of Water in the
bottle
Refer to tables in
problem examples for A
#'s
change first number in z formula
to match what z score is asking for
00 223 22
8
8
12
22
35
12
Frequency
35
20
13
12
20
13
(Mean)
12
Mean
z
A₂1
x-xbar (x-xbar)²+f
3880
500.34 -15.34 1882.9863
5880
500.34 -10.34 1283.4539
10890
500.34
17500 500.34
10100
500.34
6630
500.34
6180 500.34
500.34
-0.64209
0.2389
0.7389
xbar
(Mean) x f
=A77 877
=A78 878
=A79*B79
=A80*880
=A81*B81
=A82 882
=A83*B83
0.2389
-0.5+C87
-5.34 627.78508
-0.34 4.0908759
4.66 433.96157
standard
deviation
9.66 1212.6306
14.66 2578.3257
500.34188034188
-(495-500.34)/F85
change first number in z formula to match what z score is asking for
8.3166
xbar
x-xbar
-SUM(C$3:C$9)/117 =A77-D77
=SUM(C$3:C$9)/117 =A78-D78
=SUM(C$3:C$9)/117 =A79-D79
-SUM(C$3:C$9)/117 A80-D80
-SUM(C$3:C$9)/117 =A81-D81
-SUM(C$3:C$9)/117 A82-D82
-SUM(C$3:C$9)/117 =A83-D83
Answers
(x-xbar) f
=E77^2*877
=E78^2*878
=E79^2*879
=E80^2 880
=E81^2*881
=E82^2*882
=E83^2*883
standard deviation -SQRT(SUM(F77:F83)/(117-1)
Formulas put in
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