What is the sound level (in decibels) of a sound whose intensity is 7.5 x 108 w/m2? 6.7 dB 7.5 dB 80 dB 67 dB

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### Question: Sound Level Calculation

**Problem Statement:**
What is the sound level (in decibels) of a sound whose intensity is \(7.5 \times 10^{-8} \, \text{W/m}^2\)?

**Options:**
- ⦾ 6.7 dB
- ⦾ 7.5 dB
- ⦾ 80 dB
- ⦾ 67 dB

### Explanation:

To calculate the sound level in decibels (dB), use the formula:
\[ L = 10 \log_{10} \left( \frac{I}{I_0} \right) \]
where:
- \( L \) is the sound level in decibels (dB),
- \( I \) is the intensity of the sound in watts per square meter (\(\text{W/m}^2\)),
- \( I_0 \) is the reference intensity, typically \( 1 \times 10^{-12} \, \text{W/m}^2 \).

Given the intensity (\( I \)) is \( 7.5 \times 10^{-8} \, \text{W/m}^2 \), substitute the values into the formula:

\[ L = 10 \log_{10} \left( \frac{7.5 \times 10^{-8}}{1 \times 10^{-12}} \right) \]

Simplify the fraction inside the logarithm:

\[ \frac{7.5 \times 10^{-8}}{1 \times 10^{-12}} = 7.5 \times 10^4 \]

Now calculate the logarithm:

\[ \log_{10} (7.5 \times 10^4) = \log_{10} (7.5) + \log_{10} (10^4) \]
\[ = \log_{10} (7.5) + 4 \]

The approximate value of \( \log_{10} (7.5) \) is around 0.875.

Therefore, the sound level calculation becomes:
\[ L = 10 \times (0.875 + 4) \]
\[ = 10 \times 4.875 \]
\[ = 48.75 \, \text{dB} \]

Since this value is not in the given options,
Transcribed Image Text:### Question: Sound Level Calculation **Problem Statement:** What is the sound level (in decibels) of a sound whose intensity is \(7.5 \times 10^{-8} \, \text{W/m}^2\)? **Options:** - ⦾ 6.7 dB - ⦾ 7.5 dB - ⦾ 80 dB - ⦾ 67 dB ### Explanation: To calculate the sound level in decibels (dB), use the formula: \[ L = 10 \log_{10} \left( \frac{I}{I_0} \right) \] where: - \( L \) is the sound level in decibels (dB), - \( I \) is the intensity of the sound in watts per square meter (\(\text{W/m}^2\)), - \( I_0 \) is the reference intensity, typically \( 1 \times 10^{-12} \, \text{W/m}^2 \). Given the intensity (\( I \)) is \( 7.5 \times 10^{-8} \, \text{W/m}^2 \), substitute the values into the formula: \[ L = 10 \log_{10} \left( \frac{7.5 \times 10^{-8}}{1 \times 10^{-12}} \right) \] Simplify the fraction inside the logarithm: \[ \frac{7.5 \times 10^{-8}}{1 \times 10^{-12}} = 7.5 \times 10^4 \] Now calculate the logarithm: \[ \log_{10} (7.5 \times 10^4) = \log_{10} (7.5) + \log_{10} (10^4) \] \[ = \log_{10} (7.5) + 4 \] The approximate value of \( \log_{10} (7.5) \) is around 0.875. Therefore, the sound level calculation becomes: \[ L = 10 \times (0.875 + 4) \] \[ = 10 \times 4.875 \] \[ = 48.75 \, \text{dB} \] Since this value is not in the given options,
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