What is the solution to the following differential equation? y = (x + y)², y (0) = 0 du As a hint, remember that f 1+u² tan (u). O (x) tan(x) O y (x) tan(x) O y (x) -x + tan(x) O y (2) = x tan(x)

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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**Problem Statement:**

What is the solution to the following differential equation?

\[ y' = (x + y)^2, \quad y(0) = 0 \]

As a hint, remember that 

\[
\int \frac{du}{1 + u^2} = \tan^{-1}(u).
\]

**Solution Options:**

1. \( y(x) = -x - \tan(x) \)
2. \( y(x) = \tan(x) \)
3. \( y(x) = -x + \tan(x) \)
4. \( y(x) = x - \tan(x) \)
Transcribed Image Text:**Problem Statement:** What is the solution to the following differential equation? \[ y' = (x + y)^2, \quad y(0) = 0 \] As a hint, remember that \[ \int \frac{du}{1 + u^2} = \tan^{-1}(u). \] **Solution Options:** 1. \( y(x) = -x - \tan(x) \) 2. \( y(x) = \tan(x) \) 3. \( y(x) = -x + \tan(x) \) 4. \( y(x) = x - \tan(x) \)
Expert Solution
Step 1

The given differential equation is 

y'= (x+y)2, y(0)= 0 

We have to find the solution of this differential equation.

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