What is the solution of the DE (x – 2y + 1) dx + (4x – 3y – 6) dy = 0? A. (x + 3y + 3)5 = c(x + y + 5) В. (х- Зу - 3)5 %3 с(х — у - 5) C. (x + 3y + 3)5 = c(x – y – 5) D. (x - 3y - 3)5 = c(x + y + 5) Answer: What is the differential equation whose solution is given by x+1 = m? Where m varies as any real number. A. (y – 1)dx = (x + 1)dy В. (у - 1) dx 3D- (x + 1)dy C. -(y - 1)dx = (x + 1)dy D. -(y - 1)dx + (x + 1)dy = 0 Answer:

Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
What is the solution of the DE
(x – 2y + 1) dx + (4x – 3y – 6) dy = 0?
A. (x + 3y + 3)5 = c(x + y + 5)
В. (х- Зу - 3)5 %3 с(х — у - 5)
C. (x + 3y + 3)5 = c(x – y – 5)
D. (x - 3y - 3)5 = c(x + y + 5)
Answer:
What is the differential equation whose solution is given by
x+1
= m?
Where m varies as any real number.
A. (y – 1)dx = (x + 1)dy
В. (у - 1) dx 3D-
(x + 1)dy
C. -(y - 1)dx = (x + 1)dy
D. -(y - 1)dx + (x + 1)dy = 0
Answer:
Transcribed Image Text:What is the solution of the DE (x – 2y + 1) dx + (4x – 3y – 6) dy = 0? A. (x + 3y + 3)5 = c(x + y + 5) В. (х- Зу - 3)5 %3 с(х — у - 5) C. (x + 3y + 3)5 = c(x – y – 5) D. (x - 3y - 3)5 = c(x + y + 5) Answer: What is the differential equation whose solution is given by x+1 = m? Where m varies as any real number. A. (y – 1)dx = (x + 1)dy В. (у - 1) dx 3D- (x + 1)dy C. -(y - 1)dx = (x + 1)dy D. -(y - 1)dx + (x + 1)dy = 0 Answer:
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