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What is the solution of given initial value problem? = y + sin t dt2 d'y dz + cos t dt dt2 a (0) = 1, a'(0) = 0, y(0) = -1, y'(0) = -1 O a. a(t) = cos t, y(t) = cost – sint O b. (t) = sin t, y(t) = - cost - sint O c. a(t) = cos t, y(t) = - cost – sin t O d. r(t) = cos t, y(t) = - cost + sin t O e. r(t) = sin t, y(t) = cost + sin t

What is the solution of given initial value problem? = y + sin t dt2 d'y dz + cos t dt dt2 a (0) = 1, a'(0) = 0, y(0) = -1, y'(0) = -1 O a. a(t) = cos t, y(t) = cost – sint O b. (t) = sin t, y(t) = - cost - sint O c. a(t) = cos t, y(t) = - cost – sin t O d. r(t) = cos t, y(t) = - cost + sin t O e. r(t) = sin t, y(t) = cost + sin t

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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What is the solution of given initial value problem? =y + sin t dt2 d?y dr + cos t dt dt? ¤(0) = 1, a'(0) = 0, y(0) = -1, y'(0) = -1 O a. x(t) = cos t, y(t) = cost – sin t O b. x(t) = sin t, y(t) = cost - sin t O c. r(t) = cos t, y(t) -cos t – sin t %3D O d. r(t) = cos t, y(t) = cos t + sin t O e. r(t) = sint, y(t) = cost + sin t е.
Transcribed Image Text:What is the solution of given initial value problem? =y + sin t dt2 d?y dr + cos t dt dt? ¤(0) = 1, a'(0) = 0, y(0) = -1, y'(0) = -1 O a. x(t) = cos t, y(t) = cost – sin t O b. x(t) = sin t, y(t) = cost - sin t O c. r(t) = cos t, y(t) -cos t – sin t %3D O d. r(t) = cos t, y(t) = cos t + sin t O e. r(t) = sint, y(t) = cost + sin t е.
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