What is the solution of given initial value problem? =y + sin t dt2 da + cost dt - dt2 * (0) = 1, a (0) = 0, 3(0) = -1, 3 (0) = -1 a. (t) = sin t, y(t) = – cost - sint O b. * (t) = sin t, y(t) = cost + sin t O c. (t) = cost, y(t) = cost - sin t O d. « (t) = cost, y(t) = cost - sin t O e. * (t) = cost, y(t) = - cos t + sin t

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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What is the solution of given initial value problem?
=y + sin t
dt2
da
+ cost
dt
-
dt2
* (0) = 1, a (0) = 0, 3(0) = -1, 3 (0) = -1
a. (t) = sin t, y(t) = - cost - sint
O b. * (t) = sin t, y(t) = cost + sin t
O c. (t) = cost, y(t) =
cost - sin t
O d. « (t) = cost, y(t) = cost - sin t
O e. « (t) = cost, y(t) = - cos t + sin t
Transcribed Image Text:What is the solution of given initial value problem? =y + sin t dt2 da + cost dt - dt2 * (0) = 1, a (0) = 0, 3(0) = -1, 3 (0) = -1 a. (t) = sin t, y(t) = - cost - sint O b. * (t) = sin t, y(t) = cost + sin t O c. (t) = cost, y(t) = cost - sin t O d. « (t) = cost, y(t) = cost - sin t O e. « (t) = cost, y(t) = - cos t + sin t
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