What is the slope-intercept equation for the linear function represented by the table? X 03 6 9 12 y 3 1 -1 -3 -5 A. y = -x - 3 B. y = x - 3 c. y = OD. y = x +3 x +3

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### Slope-Intercept Equation of a Linear Function

**Question:**

What is the slope-intercept equation for the linear function represented by the table?

**Table:**

\[
\begin{array}{|c|c|c|c|c|c|}
\hline
x & 0 & 3 & 6 & 9 & 12 \\
\hline
y & 3 & 1 & -1 & -3 & -5 \\
\hline
\end{array}
\]

**Options:**

A. \( y = -\frac{2}{3}x - 3 \)

B. \( y = \frac{2}{3}x - 3 \)

C. \( y = -\frac{2}{3}x + 3 \)

D. \( y = \frac{2}{3}x + 3 \)

---

To determine the slope-intercept equation of a linear function, we need to find the slope (\(m\)) and the y-intercept (\(b\)) of the line. The general form of the slope-intercept equation is:

\[
y = mx + b
\]

Let's calculate the slope (\(m\)):

The slope of the line is given by the formula:

\[
m = \frac{\Delta y}{\Delta x} = \frac{y_2 - y_1}{x_2 - x_1}
\]

Using the points (0, 3) and (3, 1):

\[
m = \frac{1 - 3}{3 - 0} = \frac{-2}{3}
\]

So, the slope (\(m\)) is \(-\frac{2}{3}\).

Next, let's find the y-intercept (\(b\)). The y-intercept is the value of \(y\) when \(x = 0\), which is given directly in the table as \(3\).

Substituting these values into the slope-intercept form equation:

\[
y = -\frac{2}{3}x + 3
\]

Therefore, the correct equation is:

C. \( y = -\frac{2}{3}x + 3 \)
Transcribed Image Text:--- ### Slope-Intercept Equation of a Linear Function **Question:** What is the slope-intercept equation for the linear function represented by the table? **Table:** \[ \begin{array}{|c|c|c|c|c|c|} \hline x & 0 & 3 & 6 & 9 & 12 \\ \hline y & 3 & 1 & -1 & -3 & -5 \\ \hline \end{array} \] **Options:** A. \( y = -\frac{2}{3}x - 3 \) B. \( y = \frac{2}{3}x - 3 \) C. \( y = -\frac{2}{3}x + 3 \) D. \( y = \frac{2}{3}x + 3 \) --- To determine the slope-intercept equation of a linear function, we need to find the slope (\(m\)) and the y-intercept (\(b\)) of the line. The general form of the slope-intercept equation is: \[ y = mx + b \] Let's calculate the slope (\(m\)): The slope of the line is given by the formula: \[ m = \frac{\Delta y}{\Delta x} = \frac{y_2 - y_1}{x_2 - x_1} \] Using the points (0, 3) and (3, 1): \[ m = \frac{1 - 3}{3 - 0} = \frac{-2}{3} \] So, the slope (\(m\)) is \(-\frac{2}{3}\). Next, let's find the y-intercept (\(b\)). The y-intercept is the value of \(y\) when \(x = 0\), which is given directly in the table as \(3\). Substituting these values into the slope-intercept form equation: \[ y = -\frac{2}{3}x + 3 \] Therefore, the correct equation is: C. \( y = -\frac{2}{3}x + 3 \)
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