What is the runtime of the following code: for (int i = 0; i < 100; i++) { for (int j = 0; j < 100; j++) { System.out.println(i * j); } 00(1) O(log(n)) O(n) (²)
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- 5. What is wrong with the following function and why? int *setup(int n){ int a[n); for(int i=0; iWhat’s the output?explain step by step please.List two ways to rewrite the following code with code optimization methods for(i=0;ivoid- find and replace (char A, char *oldc, char newc) for (int i-0; i<5; i++) for (int j%3D0; j<3; j++) == oldc[jl) A[i] = newc[j]: if (A[i] The procedure is tested with the following four test cases. 1. oldc 2. oldc "abc" , newc = "cde", newc = "dab" "bcd" 3. oldc 4. oldc = "abc", newc = "bca", newc= "cda" = "bac"def hailstone(n): h.append(int(n)) if n == 1: return h while n != 1: if n % 2 == 0: return hailstone(int(n/2)) else: return hailstone(int(3*n + 1))y=int(input("N: "))if y <= 0: print("N must be positive!")else: print("Hailstone sequences for 1 to " + str(y) + ": ") m=0; i=1 for x in range(1, y+1): n = i h = [] h = hailstone(n) print(*h) print(",") s=len(h) if s > m: m=s flag=n i=i+1 print("First longest sequence found in n =", + flag ) How can I fix this code if I want a comma between each number, not each line?Recommended textbooks for youDatabase System ConceptsComputer ScienceISBN:9780078022159Author:Abraham Silberschatz Professor, Henry F. Korth, S. SudarshanPublisher:McGraw-Hill Education
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