Please don't provide handwritten solution 10. What is the root mean square velocity of O₂ gas at 25 °C? [Given is: Urms = V(3RT/M);R = 8.3145 J/(K*mol)]a) 300 m/sb) 342.2 m/sc) 600 m/sd) 482 m/se) 442.2 m/s

The formula for root mean square velocity,where R=universal gas constant = 8.3145 J/mol*K…

Answered: - What is the root mean square velocity…

- What is the root mean square velocity of Oz gas at 25 °C? [Given is: Urms= V(3RT/M); R = 8.3145 J/(K*mol)] a) 300 m/s b) 342.2 m/s c) 600 m/s d) 482 m/s e) 442.2 m/s

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Mole Concept

Mole concept is a method to determine the amount of any substance that consists of some elemental particles using a grouping unit called ‘mole’. The mole concept enables one to handle the large amount of small elementary particles. The mole concept can be used in many calculations related to mole calculation, molar amount, mole ratio, and so on, which are significant in chemistry.

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Please don't provide handwritten solution

10. What is the root mean square velocity of O₂ gas at 25 °C? [Given is: Urms = V(3RT/M);
R = 8.3145 J/(K*mol)]
a) 300 m/s
b) 342.2 m/s
c) 600 m/s
d) 482 m/s
e) 442.2 m/s

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InXaSvlwj83vl%2fy7QpV7np6yzrMrwEZX Learning map/ Unit 4: Spaced Practice Assessment 1 Do assessment ssessment 1 Question number 11 How many total moles of ions will form when one mole of Na,SO4(s) is dissolved to form an aqueous solution? 3. Question number 12
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The equivalence point is defined as moles acid = moles base. So first, let's calculate the initial moles of base we used. molpase Mpase = Volsoiution Molarity base = 0.100 (M) Volume of solution= _50.00 mL Moles of base = _5.00 mmol So, we need 5.00 mmol of acid (titrant) to be delivered to the analyte. Since we know the molarity of the acid and moles of acid, we just need to solve for the volume of acid (titrant) to be added. molacid Voladded Macid Molarity acid = . 0.200 (M) Moles of acid = _5.00 (mmol) Volume of acid needed to reach equivalence point (mL)
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