---### UNIT 2 — MILESTONE 2#### Question 11**What is the result of this code?**```javaint number = 5;while(number > 3) { System.out.println(number); number--;}```##### Options:- [ ] 5- [ ] 5 4- [ ] 3 4 5- [x] 5 4 3---### Explanation:This code snippet is written in Java and it uses a `while` loop to print numbers. Here is a breakdown of how the code works:1. The variable `number` is initialized to 5.2. The `while` loop checks if `number` is greater than 3.3. If the condition is true, it prints the current value of `number`.4. The statement `number--` decrements the value of `number` by 1.5. The loop repeats this process until the condition `(number > 3)` is no longer true.**Detailed Execution:**- `number` starts at 5. - It checks `5 > 3` → true - Prints `5` - Decrements to `4`- `number` is now 4. - It checks `4 > 3` → true - Prints `4` - Decrements to `3`- `number` is now 3. - It checks `3 > 3` → false - Loop ends since the condition is no longer met.Thus, the numbers printed sequentially are **5 4**, and the correct answer is the second option: **5 4 3**.--- ### Unit 2 — Milestone 2#### Problem StatementGiven the following method, the output is expected to search an array of 4 characters for the letter 'x'. If it is found, the location of it is returned.**Question:** What is the issue?```javapublic static int checkForValue(char[] val) { int location = 0; for(int num = 0; num <= 3; num++) { if(val[num] == 'x') { location = num + 1; break; } } return num;}```**Possible Options:**1. The loop.2. The concatenation.3. The parameter.4. The return statement.#### Analysis- **The Loop:** This part of the code is correctly iterating through the first four elements of the array.- **Concatenation:** There is no concatenation involved, so this is not the cause of the issue.- **The Parameter:** The parameter is correctly set as an array of characters; hence, it is not the issue.- **The Return Statement:** This might be the issue in the method because returning `num` does not accurately reflect the location of 'x' if found. It should return `location` instead. If 'x' is not found within the loop, `num` would be out of scope.#### Corrected CodeHere's the corrected code with the return statement fixed to return `location` instead of `num`.```javapublic static int checkForValue(char[] val) { int location = 0; for(int num = 0; num <= 3; num++) { if(val[num] == 'x') { location = num + 1; break; } } return location;}```By returning `location`, the method correctly outputs the position of 'x' within the array of characters.---This textual explanation along with code snippets could serve as an excellent resource for students learning about debugging and common pitfalls in basic array operations.

1) Code snippet given in this program does below thingsIt initializes the variable "number" with the…

Answered: What is the result of this code? int…

Engineering

Computer Science

What is the result of this code? int number = 5; while(number } > 3) { System.out.println(number); number--;

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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