What is the repulsive force between two pith balls that are 13.0 cm apart and have equal charges of -29.0 nC?

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A: frictional force (f) = 100 N gravitational force = 600 N Normal force = gravitational force= 600 N

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A: Solution:-Given that

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A: Solution

Q: -please see attached, only b and c

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A: Given: Give an example of a dynamic equilibrium & explain

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A: Note: As per the student's request, here I am giving only the solution to part 4) and 5)

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