What is the rate law for the following mechanism:2 A+B2C (fast equilibrium; rate of forward reaction: k], rate of reverse reaction: k.1)B+C -D (slow, rate: k2)D - E(fast, rate: k3)Rate= k2 (k1/k.1) [A]²[B}²OA.O B. Rate= (k1 k1) [A][B]²В.Rate= k2 [B][C]O D. Rate= k2 (k1/k1)[A]{{B]O E. Rate= k2 [A]²B]²Е.

Slow step is rate determining step and also we use equilibrium expression for removing intermediate…

Answered: What is the rate law for the following…

What is the rate law for the following mechanism: 2 A+B2C (fast equilibrium; rate of forward reaction: k1: rate of reverse reaction: k.1) B+C -D (slow, rate: k2) D -E (fast, rate: k3)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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