**Problem Analysis for Circuit Setup****Diagram Description:**The diagram shows an electrical circuit consisting of the following components:- An ammeter labeled "AM1" on the left side.- A 12V battery in the center.- A lamp with a resistance of 10 ohms on the right side.The components are connected in parallel, with the ammeter and the lamp both directly connected to the battery terminals.**Question:**What is the problem with the following setup? (The meter on the left is an ammeter). Mark all TRUE statements.**Options:**1. ☐ The meter will short out the voltage supply.2. ☐ The meter may be damaged due to an excess of current.3. ☐ The meter is NOT in series with any load.4. ☐ There is nothing wrong with this setup.5. ☐ The meter will not be able to measure that much voltage.

Answered: What is the problem with the following…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

See similar textbooks

Related questions

Concept explainers

Question

**Problem Analysis for Circuit Setup**

**Diagram Description:**

The diagram shows an electrical circuit consisting of the following components:

- An ammeter labeled "AM1" on the left side.
- A 12V battery in the center.
- A lamp with a resistance of 10 ohms on the right side.

The components are connected in parallel, with the ammeter and the lamp both directly connected to the battery terminals.

**Question:**
What is the problem with the following setup? (The meter on the left is an ammeter). Mark all TRUE statements.

**Options:**

1. ☐ The meter will short out the voltage supply.
2. ☐ The meter may be damaged due to an excess of current.
3. ☐ The meter is NOT in series with any load.
4. ☐ There is nothing wrong with this setup.
5. ☐ The meter will not be able to measure that much voltage.

Expert Solution

Step 1

Ammeter having very negligible of resistance. in ideal case ammeter resistance is become 0 ohm -

1. Due to 0 resistance voltage source is short circuited. Hence statement one is true.

"The meter will short out the voltage supply."

2. when ammeter connected in parallel as we know that current always follow from low resistance path. So that large amount of current will flow through the ammeter due to this high amount of current ammeter will burn the fuse or can damage the ammeter. hence statement 2 is true

"The meter may be damaged due to an excess current."

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.

Similar questions