What is the probability tihat the salary of a randomly selected bank teller will be between D0.5328 D0.1498 D0.5000 D0.8413 0.3085 Which of the following Excel commands can be used to calculate the probability that a ra eller has a monthly salary of more than R23500? D= 1 NORM.DIST ( 23500 ; 22500 ; 1000 ; FALSE) O= 1 - NORM.INV ( 23500 ; 22500 ; 1000; TRUE ) = 1 - NORM.DIST ( 23500 ; 22500 ; 1000 ; TRUE) = NORM.INV ( 23500 ; 22500 ; SQRT(1000) ; FALSE ) = NORM.DIST ( 23500 ; 22500 ; 1000 ; FALSE ) ary is a bank teller. Only 2.5% of bank tellers earn more than her. What is Marys mont R 22471 R 23174 R 21825 R 20540

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Questian 8
The monthly salary of bank tellers is known to be normally distributed with mean of R22500 and a standard
deviation of R1000.
Not yet
Finish attm
answered
Time left
Marked aut of
What is the probability that the salary of a randomly selected bank teller will be between R22000 and R23500?
3.00
00.5328
P Flag question
00.1498
00.5000
00.8413
00.3085
Which of the following Excel commands can be used to calculate the probability that a randomly selected bank
teller has a monthly salary of more than R23500?
O= 1- NORM.DIST ( 23500 ; 22500 ; 1000 ; FALSE)
O= 1 - NORM.INV ( 23500 ; 22500 ; 1000 ; TRUE )
O= 1- NORM.DIST ( 23500 ; 22500 ; 1000 ; TRUE )
O= NORM.INV ( 23500; 22500 ; SQRT(1000) ; FALSE )
O= NORM.DIST ( 23500 ; 22500 ; 1000 ; FALSE )
Mary is a bank teller. Only 2.5% of bank tellers earn more than her. What is Marys monthly salary?
OR 22471
OR 23174
OR 21825
R 20540
Transcribed Image Text:Questian 8 The monthly salary of bank tellers is known to be normally distributed with mean of R22500 and a standard deviation of R1000. Not yet Finish attm answered Time left Marked aut of What is the probability that the salary of a randomly selected bank teller will be between R22000 and R23500? 3.00 00.5328 P Flag question 00.1498 00.5000 00.8413 00.3085 Which of the following Excel commands can be used to calculate the probability that a randomly selected bank teller has a monthly salary of more than R23500? O= 1- NORM.DIST ( 23500 ; 22500 ; 1000 ; FALSE) O= 1 - NORM.INV ( 23500 ; 22500 ; 1000 ; TRUE ) O= 1- NORM.DIST ( 23500 ; 22500 ; 1000 ; TRUE ) O= NORM.INV ( 23500; 22500 ; SQRT(1000) ; FALSE ) O= NORM.DIST ( 23500 ; 22500 ; 1000 ; FALSE ) Mary is a bank teller. Only 2.5% of bank tellers earn more than her. What is Marys monthly salary? OR 22471 OR 23174 OR 21825 R 20540
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