What is the pressure in a 6.00 L tank with 20.0 grams of nitrogen gas at 385 K?

Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Question 13 of 15**

What is the pressure in a 6.00 L tank with 20.0 grams of nitrogen gas at 385 K?

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This question likely involves the application of the Ideal Gas Law, given the provided values for volume, mass, and temperature. To solve this, one would typically convert the mass of the nitrogen gas to moles and use the formula:

\[ PV = nRT \]

Where:
- \( P \) is the pressure,
- \( V \) is the volume (6.00 L),
- \( n \) is the number of moles of gas,
- \( R \) is the ideal gas constant (0.0821 L atm / mol K),
- \( T \) is the temperature in Kelvin (385 K). 

To find the number of moles (\( n \)), divide the mass by the molar mass of nitrogen (\( \text{N}_2 \), approximately 28.02 g/mol).

This question requires calculating the pressure using the values and concepts provided.
Transcribed Image Text:**Question 13 of 15** What is the pressure in a 6.00 L tank with 20.0 grams of nitrogen gas at 385 K? --- This question likely involves the application of the Ideal Gas Law, given the provided values for volume, mass, and temperature. To solve this, one would typically convert the mass of the nitrogen gas to moles and use the formula: \[ PV = nRT \] Where: - \( P \) is the pressure, - \( V \) is the volume (6.00 L), - \( n \) is the number of moles of gas, - \( R \) is the ideal gas constant (0.0821 L atm / mol K), - \( T \) is the temperature in Kelvin (385 K). To find the number of moles (\( n \)), divide the mass by the molar mass of nitrogen (\( \text{N}_2 \), approximately 28.02 g/mol). This question requires calculating the pressure using the values and concepts provided.
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