What is the potential of a cell made up of Zn/ Zn2+ and Cu/ Cu+ half-cells at 25°C if [Zn2*1 = 0.11 M and [Cu2] = 0.81 M ? V

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### Electrochemical Cell Potential Calculation

**Problem Statement:**

Enter your answer in the provided box.

What is the potential of a cell made up of Zn / Zn²⁺ and Cu / Cu²⁺ half-cells at 25°C if 
\[ \left[ \text{Zn}^{2+} \right] = 0.11 \, \text{M} \]
and 
\[ \left[ \text{Cu}^{2+} \right] = 0.81 \, \text{M} ? \]

**Answer Box:**

\[ \boxed{} \text{ V} \]

**Explanation:**

To find the potential of the electrochemical cell, use the Nernst Equation:

\[ E_{\text{cell}} = E^\circ_{\text{cell}} - \frac{0.0592}{n} \log Q \]

Where:
- \( E^\circ_{\text{cell}} \) is the standard cell potential
- \( n \) is the number of moles of electrons transferred
- \( Q \) is the reaction quotient 

For the Zn/Cu cell, the redox reactions and their standard potentials (at 25°C) are:

\[ \text{Zn} \rightarrow \text{Zn}^{2+} + 2e^- \quad (E^\circ_{\text{Zn/Zn}^{2+}} = -0.76\, \text{V}) \]

\[ \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu} \quad (E^\circ_{\text{Cu}^{2+}/\text{Cu}} = +0.34 \, \text{V}) \]

So, the overall standard cell potential is:

\[ E^\circ_{\text{cell}} = E^\circ_{\text{Cu}^{2+}/\text{Cu}} - E^\circ_{\text{Zn}/\text{Zn}^{2+}} \]

\[ E^\circ_{\text{cell}} = 0.34\, \text{V} - (-0.76\, \text{V}) \]

\[ E^\circ_{\text{cell}} = 1.10\, \text{V} \]

Next, calculate the reaction quotient \( Q \):

\[ Q = \frac{ \left[ \text{Zn}^{2+} \right] }{ \left[ \text
Transcribed Image Text:### Electrochemical Cell Potential Calculation **Problem Statement:** Enter your answer in the provided box. What is the potential of a cell made up of Zn / Zn²⁺ and Cu / Cu²⁺ half-cells at 25°C if \[ \left[ \text{Zn}^{2+} \right] = 0.11 \, \text{M} \] and \[ \left[ \text{Cu}^{2+} \right] = 0.81 \, \text{M} ? \] **Answer Box:** \[ \boxed{} \text{ V} \] **Explanation:** To find the potential of the electrochemical cell, use the Nernst Equation: \[ E_{\text{cell}} = E^\circ_{\text{cell}} - \frac{0.0592}{n} \log Q \] Where: - \( E^\circ_{\text{cell}} \) is the standard cell potential - \( n \) is the number of moles of electrons transferred - \( Q \) is the reaction quotient For the Zn/Cu cell, the redox reactions and their standard potentials (at 25°C) are: \[ \text{Zn} \rightarrow \text{Zn}^{2+} + 2e^- \quad (E^\circ_{\text{Zn/Zn}^{2+}} = -0.76\, \text{V}) \] \[ \text{Cu}^{2+} + 2e^- \rightarrow \text{Cu} \quad (E^\circ_{\text{Cu}^{2+}/\text{Cu}} = +0.34 \, \text{V}) \] So, the overall standard cell potential is: \[ E^\circ_{\text{cell}} = E^\circ_{\text{Cu}^{2+}/\text{Cu}} - E^\circ_{\text{Zn}/\text{Zn}^{2+}} \] \[ E^\circ_{\text{cell}} = 0.34\, \text{V} - (-0.76\, \text{V}) \] \[ E^\circ_{\text{cell}} = 1.10\, \text{V} \] Next, calculate the reaction quotient \( Q \): \[ Q = \frac{ \left[ \text{Zn}^{2+} \right] }{ \left[ \text
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