What is the position r(t) of the object as a function of time if x(0) = 0 m? Solve this by direct integration: In other words, solve via x(t) − x( S v₂ (t')dt'.

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Please explain and work out part b with plenty of explanations on the integration parts

A sin(wt), where
1. An object moves along the x-axis with a velocity given by vx(t)
3s¹ and A 1 m/s. (For an example of a physical scenario in which this type of
behavior might occur, see question 4.)
W=
=
=
(a) What is the displacement Ax of the object between t = = 0 and t
=
Solve this graphically: Draw a graph of v₂ vs. t for the indicated time range,
and determine your answer entirely by examining this graph.
2 s?
(b) What is the position x(t) of the object as a function of time if x(0) = 0 m?
Solve this by direct integration: In other words, solve via x(t) − x(0)
So vz(t)dt'.
Transcribed Image Text:A sin(wt), where 1. An object moves along the x-axis with a velocity given by vx(t) 3s¹ and A 1 m/s. (For an example of a physical scenario in which this type of behavior might occur, see question 4.) W= = = (a) What is the displacement Ax of the object between t = = 0 and t = Solve this graphically: Draw a graph of v₂ vs. t for the indicated time range, and determine your answer entirely by examining this graph. 2 s? (b) What is the position x(t) of the object as a function of time if x(0) = 0 m? Solve this by direct integration: In other words, solve via x(t) − x(0) So vz(t)dt'.
Expert Solution
Step 1

(b) Given: The velocity of the object is vxt=A sinωt.

                The value of ω is 3 s-1.

                The value of A is 1 m/s.

To determine: The position of the object as a function of time. 

The velocity of the object is given as 

v=dxdt

where x is the position of the particle. 

Substitute the value of v

dxdt=A sinωtdx=A sinωt.dt

Integrate this equation on both sides of the equation 

0xdx=0tA sinωt.dtx=A0tsinωt.dtx=A×-cosωtω0t+Cx=-Acosωtω-cosω×0ω+C

 

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