What is the pOH of an aqueous solution of 3.77 x 10-2 M sodium hydroxide? pOH =

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**Question:**

What is the pOH of an aqueous solution of \(3.77 \times 10^{-2}\) M sodium hydroxide?

**Solution Box:**

pOH = [__________]

---

To solve this problem, you need to understand the concept of pOH, which is the negative logarithm of the hydroxide ion concentration \([\text{OH}^-]\). Since sodium hydroxide (NaOH) dissociates completely in water, the concentration of hydroxide ions is equal to the concentration of the NaOH solution.

Given:
- \([\text{OH}^-] = 3.77 \times 10^{-2}\) M

The formula to calculate pOH is:
\[ \text{pOH} = -\log_{10} [\text{OH}^-] \]

Plug in the given concentration:
\[ \text{pOH} = -\log_{10} (3.77 \times 10^{-2}) \]

Calculate the pOH value using this formula.
Transcribed Image Text:**Question:** What is the pOH of an aqueous solution of \(3.77 \times 10^{-2}\) M sodium hydroxide? **Solution Box:** pOH = [__________] --- To solve this problem, you need to understand the concept of pOH, which is the negative logarithm of the hydroxide ion concentration \([\text{OH}^-]\). Since sodium hydroxide (NaOH) dissociates completely in water, the concentration of hydroxide ions is equal to the concentration of the NaOH solution. Given: - \([\text{OH}^-] = 3.77 \times 10^{-2}\) M The formula to calculate pOH is: \[ \text{pOH} = -\log_{10} [\text{OH}^-] \] Plug in the given concentration: \[ \text{pOH} = -\log_{10} (3.77 \times 10^{-2}) \] Calculate the pOH value using this formula.
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