Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![## Show What You Know: pH & pOH
**Question:**
What is the pOH of a solution with \([OH^-]\) = \(6.9 \times 10^{-10}\) M? Show your work.
**Answer:**
To calculate the pOH of a solution, you can use the formula:
\[ \text{pOH} = -\log [OH^-] \]
Given:
\[ [OH^-] = 6.9 \times 10^{-10} \text{ M} \]
Steps to find the pOH:
1. Substitute the value of \([OH^-]\) into the formula.
\[ \text{pOH} = -\log (6.9 \times 10^{-10}) \]
2. Apply the logarithm rule to resolve the expression.
Using logarithms:
\[ \text{pOH} = -(\log 6.9 + \log 10^{-10}) \]
\[ \text{pOH} = -(\log 6.9 - 10) \]
\[ \text{pOH} \approx - (0.839 + (-10)) \]
\[ \text{pOH} \approx - (0.839 - 10) \]
\[ \text{pOH} \approx - 0.839 + 10 \]
\[ \text{pOH} \approx 10 - 0.839 \]
\[ \text{pOH} \approx 9.16 \]
So, the pOH of the solution is approximately 9.16.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F78b0d0bb-8fd7-4c3f-81b0-257e1cc18a72%2Ffad29add-9724-4bb2-94dd-32f14f5bf15d%2F6sci5vj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:## Show What You Know: pH & pOH
**Question:**
What is the pOH of a solution with \([OH^-]\) = \(6.9 \times 10^{-10}\) M? Show your work.
**Answer:**
To calculate the pOH of a solution, you can use the formula:
\[ \text{pOH} = -\log [OH^-] \]
Given:
\[ [OH^-] = 6.9 \times 10^{-10} \text{ M} \]
Steps to find the pOH:
1. Substitute the value of \([OH^-]\) into the formula.
\[ \text{pOH} = -\log (6.9 \times 10^{-10}) \]
2. Apply the logarithm rule to resolve the expression.
Using logarithms:
\[ \text{pOH} = -(\log 6.9 + \log 10^{-10}) \]
\[ \text{pOH} = -(\log 6.9 - 10) \]
\[ \text{pOH} \approx - (0.839 + (-10)) \]
\[ \text{pOH} \approx - (0.839 - 10) \]
\[ \text{pOH} \approx - 0.839 + 10 \]
\[ \text{pOH} \approx 10 - 0.839 \]
\[ \text{pOH} \approx 9.16 \]
So, the pOH of the solution is approximately 9.16.
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