What is the pH of the solution when Julianna has added 30.00 mL of the 0.50 M HCl to the 40.00 mL of 0.25 M methylamine? Kb = 4.4 x 10-4 pH = [?] pH @ 30 mL acid Enter

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A: Given that:         50.00 ML of 0.250m  NaC7H5O2         Molarity =molesvolume         moles of…

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A: given: 61 ml of weak base is titrated with 20 ml of 1.1 M strong acid HCl. at equivalence point,…

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Q: 10) You make a solution that has a final concentration of 0.400 M acetic acid and 0.350 M sodium…

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Q: Calculate the pH of a solution prepared by adding 30.0 mLs of 0.20 M HCl to 50.0 mLs of 0.10 M…

A: Given: Concentration of HCl = 0.20 M Volume of HCl solution = 30.0 mL = 0.030 L…

Q: 1. a. What is the pH of a solution prepared by adding 25.0 mL of 0.10 M acetic acid (Ka = 1.8 x…

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Q: olution is made by mixing 185 mL of 0.100 M formic acid (Ka = 1.7 x 10-4 ) with 190. mL of 0.100 M…

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A: Dear student I have given answer to your question in the image format.

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Q: What is the pH of the solution when Caitlin has added 50.00 mL of the 0.25 M LIOH to the 25.00 mL of…

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Q: Calculate the pH of the solution after 500 mL of the titrant have been added. Express your answer to…

A: The concentration of the acetic acid is Ca = 0.010 M,The volume of the the acetic acid is Va = 500…

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Q: Calculate the pH at the equivalence point of 25.0 mL solution of ascorbic acid, titrated with 45.3…

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Q: Determine the Ka value [H +]eq Solution 1 3.98 X 10-3 M Solution 2 6.03 X 10-4 M Solution 3…

A: Hello. Since your question has multiple sub-parts, we will solve the first three sub-parts for you.…

Q: Using only the Henderson-Hasselbalch equation, what is the pH of a solution that is 0.22M phenol,…

A: Given: Molarity of phenol = 0.22 M Molarity of sodium phenoxide = 0.29 M Ka of phenol = 1.3×10-8

Q: The [H+] = 1.1 x 10-3 M for the NaF / HF solution in the previous step. What is the pH of the…

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Q: What volume (in milliliters) of 0.180 M NaOH should be added to a 0.130 L solution of 0.0210 M…

A: Molarity of NaOH = 0.180 M Molarity of glycine hydrochloride = 0.0210 MVolume of glycine…

Q: Select the mixture which is capable of tolerating the addition of a strong acid without altering the…

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Q: What is the pH of a solution made from adding 10.00 mL of 0.15 M Na₂HASO4 to 25.00 mL of 0.10 M…

A: volme of Na2HAsO4=10.00 mLconcentration of Na2HAsO4=0.15 Mvolume of NaH2AsO4 =25.00 mLconcentration…

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A: Buffer solution is mixture of weak acid and its salt. Here acid used is acetic acid and salt is…

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A: The question is based on the concept of the pH of the solution.It is defined as a negative logarithm…

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Q: The next questions are related to the titration of 25.00 mL of a 0.0950 M acetic acid solution with…

A: “Since you have posted a question with multiple sub parts, we will provide the solution only to the…

Q: What is the pH of a solution created by mixing 25.00 mL of 0.10 M formic acid and 25.00 mL of 0.10 M…

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