**Determining the pH of Sodium Lactate Solution**To find the pH of a sodium lactate solution, consider the following equilibrium reaction:\[ \text{C}_3\text{H}_5\text{O}_3^- + \text{H}_2\text{O} \rightleftharpoons \text{HC}_3\text{H}_5\text{O}_3 + \text{OH}^- \]Given data:- The initial concentration of lactic acid ion (\(\text{C}_3\text{H}_5\text{O}_3^-)\) is \(3.22 \times 10^{-1}\) M.- The acid dissociation constant (\(K_a\)) for lactic acid (\(\text{HC}_3\text{H}_5\text{O}_3\)) is \(1.38 \times 10^{-4}\).**Calculation Setup:**- Using the expression for the equilibrium constant (\(K_b\)) for the reaction above and the relationship between \(K_a\) and \(K_b\):\[ K_b = \frac{K_w}{K_a} \]where \(K_w\) is the ion-product constant of water (\(1 \times 10^{-14}\)).- Calculate \(K_b\):\[ K_b = \frac{1 \times 10^{-14}}{1.38 \times 10^{-4}} \approx 7.25 \times 10^{-11} \]- Apply the ICE (Initial, Change, Equilibrium) method to find the concentration of \(\text{OH}^-\) ions at equilibrium, which can then be used to find the pOH and subsequently the pH.**Final Calculation:**- With the concentration of \(\text{OH}^-\) found, convert to pOH.- Use the relation \( \text{pH} + \text{pOH} = 14 \) to find the pH.The outlined process explains how to determine the pH for the given sodium lactate solution based on its initial concentration and dissociation constants. The exact numeric solution requires solving the equilibrium expression through iterative or algebraic methods.**User Interaction:**- The input box at the bottom labeled "pH of NaC3H5O3" allows users to enter their calculated pH value.

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Answered: What is the pH of the sodium lactate…

What is the pH of the sodium lactate solution? C3H5O3 + H₂O = HC3H5O3 + OH- [C3H5O3] = 3.22 × 10-¹ M Ka(HC3H503) = 1.38 x 10-4 pH = [?] pH of NaC₂H₂O Enter

Chemistry: An Atoms First Approach

2nd Edition

ISBN:9781305079243

Author:Steven S. Zumdahl, Susan A. Zumdahl

Publisher:Steven S. Zumdahl, Susan A. Zumdahl

Chapter12: Chemical Equilibrium

Section: Chapter Questions

Problem 2RQ: What is the law of mass action? Is it true that the value of K depends on the amounts of reactants...

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