What is the pH of a 0.20 M solution of NH4CI? K(NH3)= 1.8 x 10-5 O pH = 10.25 O pH = 3.74 O pH = 4.98 O pH = 6.53 O pH = 9.02 NH4 (aq) + H2O(1) H3O+(aq) + NH3(aq)

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What is the pH of a 0.20 M solution of NH4CI?
K(NH3)= 1.8 x 10-5
O pH = 10.25
O pH = 3.74
O pH = 4.98
O pH = 6.53
O pH = 9.02
NH4 (aq) + H2O(1) H3O+(aq) + NH3(aq)
Transcribed Image Text:What is the pH of a 0.20 M solution of NH4CI? K(NH3)= 1.8 x 10-5 O pH = 10.25 O pH = 3.74 O pH = 4.98 O pH = 6.53 O pH = 9.02 NH4 (aq) + H2O(1) H3O+(aq) + NH3(aq)
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