What is the pH of 0.89 M lithium acetate at 25°C? K,-1.96 x 105 (Type in your answer to 3 sig figs)

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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**Question:**
What is the pH of 0.89 M lithium acetate at 25°C? The ionization constant \( K_a = 1.96 \times 10^{-5} \). (Type in your answer to 3 significant figures)

**Guidance:**
To calculate the pH, consider the following steps:

1. **Dissociation Equation:**
   Write the dissociation equation for lithium acetate in water and identify it as a weak acid.

2. **Expression for \( K_a \):**
   Use the expression for the acid dissociation constant to set up the equation: 
   \[
   K_a = \frac{[H^+][A^-]}{[HA]}
   \]

3. **Assumption for Weak Acids:**
   Assume that the change in concentration of the acid (\([HA]\)) due to dissociation is negligible compared to its initial concentration.

4. **Solve for [H⁺]:**
   Use the equilibrium expression to determine the \([H^+]\).

5. **Calculate pH:**
   Determine the pH using the formula:
   \[
   \text{pH} = -\log[H^+]
   \]

Ensure the answer is typed to three significant figures as requested.
Transcribed Image Text:**Question:** What is the pH of 0.89 M lithium acetate at 25°C? The ionization constant \( K_a = 1.96 \times 10^{-5} \). (Type in your answer to 3 significant figures) **Guidance:** To calculate the pH, consider the following steps: 1. **Dissociation Equation:** Write the dissociation equation for lithium acetate in water and identify it as a weak acid. 2. **Expression for \( K_a \):** Use the expression for the acid dissociation constant to set up the equation: \[ K_a = \frac{[H^+][A^-]}{[HA]} \] 3. **Assumption for Weak Acids:** Assume that the change in concentration of the acid (\([HA]\)) due to dissociation is negligible compared to its initial concentration. 4. **Solve for [H⁺]:** Use the equilibrium expression to determine the \([H^+]\). 5. **Calculate pH:** Determine the pH using the formula: \[ \text{pH} = -\log[H^+] \] Ensure the answer is typed to three significant figures as requested.
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