What is the period of a pendulum if its string is 0.75 m long and the object at the end has a mass of 0.25 kg? Your answer: 1.0 s 1.7 s 3.0 s O 3.6 s

College Physics
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ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:Paul Peter Urone, Roger Hinrichs
Chapter16: Oscillatory Motion And Waves
Section: Chapter Questions
Problem 8CQ: Pendulum clocks are made to run at the correct rate by adjusting the pendulum's length. Suppose you...
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### Pendulum Period Calculation

#### Question:
What is the period of a pendulum if its string is 0.75 m long and the object at the end has a mass of 0.25 kg?

#### Options:
- ○ 1.0 s
- ○ 1.7 s
- ○ 3.0 s
- ○ 3.6 s

---

### Explanation:
The period \( T \) of a simple pendulum, which is independent of the mass of the bob, is given by:

\[ T = 2\pi \sqrt{\frac{L}{g}} \]

Where:
- \( T \) is the period of the pendulum,
- \( L \) is the length of the string (0.75 m in this case),
- \( g \) is the acceleration due to gravity (approximately 9.81 m/s² on the surface of the Earth).

Replacing the given values into the formula:

\[ T = 2\pi \sqrt{\frac{0.75}{9.81}} \]

#### Calculation:
\[ \sqrt{\frac{0.75}{9.81}} \approx \sqrt{0.0765} \approx 0.2766 \]

\[ T \approx 2\pi \times 0.2766 \approx 1.737 \text{ s} \]

Hence, the period of the pendulum is approximately 1.7 seconds.

### Answer:
- ○ 1.7 s
Transcribed Image Text:### Pendulum Period Calculation #### Question: What is the period of a pendulum if its string is 0.75 m long and the object at the end has a mass of 0.25 kg? #### Options: - ○ 1.0 s - ○ 1.7 s - ○ 3.0 s - ○ 3.6 s --- ### Explanation: The period \( T \) of a simple pendulum, which is independent of the mass of the bob, is given by: \[ T = 2\pi \sqrt{\frac{L}{g}} \] Where: - \( T \) is the period of the pendulum, - \( L \) is the length of the string (0.75 m in this case), - \( g \) is the acceleration due to gravity (approximately 9.81 m/s² on the surface of the Earth). Replacing the given values into the formula: \[ T = 2\pi \sqrt{\frac{0.75}{9.81}} \] #### Calculation: \[ \sqrt{\frac{0.75}{9.81}} \approx \sqrt{0.0765} \approx 0.2766 \] \[ T \approx 2\pi \times 0.2766 \approx 1.737 \text{ s} \] Hence, the period of the pendulum is approximately 1.7 seconds. ### Answer: - ○ 1.7 s
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