What is the period of a pendulum consisting of a 24-kg object swinging on a 2-m string? Use acceleration due to gravity 9.8 m/s2.
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![What is the period of a pendulum consisting of a 24-kg object swinging on a 2-m string? Use
acceleration due to gravity 9.8 m/s.
ROUND OFF ANSWER UP TO 2 DECIMAL PLACES. INPUT BOTH THE NUMBER AND THE FIRST LETTER OF THE UNIT.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0d149156-744f-4ca5-aaf6-55e55d065b5a%2F485f412b-9041-40e3-8162-c35d66d5eb9d%2Fofos50q_processed.png&w=3840&q=75)
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- How do you determine the gravitational acceleration on a planet where the period of a 1.90 m long pendulum is 2.78 s, and express the result in g = in m/s^2?A 50 cm long spring with spring constant 257 N/m has a mass 1.9 kg attached to it, and it can oscillate on a horizontal table without any friction. When the spring is pulled so that its length is 55 cm, what is the magnitude of the maximum acceleration of the mass? Give your answer in m/s?.A scientist wishes to determine the acceleration of gravity on the surface of the planet Nos'Kere by experimenting with a pendulum. The length of the pendulum is 3.2 m, and the period of the pendulum is 2.3 s. unit
- 5 kilogram object is suspended from a string. The string is 4 meters long. What is the period of the object ting as a pendulum? Express your answer a number of seconds, omitting the unit.A billiard ball hanging from a string acts as a pendulum whose effective length is 4.50 meters. A person sets up this pendulum in an elevator and finds that its period is 4.867 seconds. (a) Is the elevator accelerating? If so find the acceleration.The acceleration due to gravity on Planet X is 0.360 times the acceleration on Earth. What length (in cm) of simple pendulum would have a period of 1.20 s on Planet X? Round your answer to 2 decimal places.
- When a pendulum with a period of 2.00000 s in one location (g = 9.80 m/s2) is moved to a new location from one where the period is now 1.99747 s. What is the change in acceleration (in m/s2) due to gravity at its new location?A pendulum is 0.341m long and has a period of 3.207s. The pendulum is on an unknown planet. What is the gravity of the unknown planet in m/s2?The period of a simple pendulum (T) is measured as a function of length (L) on an unknown planet. The dependence of of L is linear (see the graph below). Use the slope of this graph to calculate the acceleration of gravity on this planet, in m/s2. 0.25 y = 0.0909x 0.2 0.15 0.1 0.05 Plot Area 0.5 1 1.5 2 2.5 L (m) T?/4 pi?(s')