What is the percent yield for the following reaction:3N22CO3 + 2Sc(CIO3)3 Sc2(CO2)3 + 6NACIO3If 100. g of sodium carbonate generates 100. g of sodium chlorate0%100%73.9%88.2%49.8 % Finish the sentence:When a precipitation reaction occurs, the ions that do not form the precipitate...(Hint #1: there may be more than one correct answer.)(Hint #2: there are two correct answers)are left dissolved in the solution.will boil out of the solution...form a unique compound that cannot be known to modern science.are called spectator ions.explode.form a precipitate.

Sodium carbonate reacts with the scandium chlorate to form the scandium carbonate and the sodium carbonate. The equation for the balanced chemical reaction is given below: The stoichiometry of the balanced chemical reaction states that three moles of sodium carbonate react with two moles of scandium chlorate to form one mole of scandium carbonate and six moles of sodium chlorate.We know that the molar mass of sodium carbonate is = 105.9888 g/mol The mass of three moles of sodium carbonate is =105.9888 x 3g = 317.9664 g he molar mass of sodium chlorate is = 106.44 g/mol The mass of six moles of sodium chlorate is = 106.44x6 g = 638.4 gHence we can say that: 317.9664 g of sodium carbonate forms = 638.4 g of sodium chlorate1 g of sodium carbonate forms = 638.4317.9664 g of sodium chlorate100 g of sodium carbonate forms = 638.4317.9664×100 g of sodium chlorate100 g of sodium carbonate forms = 200.77 g of sodium chlorateThe percent yield of the reaction is calculated as follows: percent yield=actual yieldtheoretical yield×100percent yield=100200.77×100percent yield=49.8 %The right option is = 49.8 % Please note: According to the guideline in one session only one question can be solved. Ask the second question in a separate session.