Show solution. Round off answer to four decimal places. Formula is given.Answer:% CaCO3 = _%weight of CaCO3 = _mg N x V x mEqsample weight(g)% рuritysx wt (g)x 100N =mEq x mL of solution= fM[(N x V)acid – (N × V)base] × mEqSx wt (g)% purity =× 100(V blank – V sample) × N × mEqsample weight (g)% purity :X 100 What is the percent of Caco, in an antacid given that a tablet weighed 1.3198 g reacted with 50.00 ml of 0.4486 N HCI thatsubsequently required 3.72 ml of 0.1277 N N2OH for back titration? Also report the milligrams of Caco, in the tablet.

From given Percentage of CaCO3 and weight of CaCO3 in milligrams is calculated analytically with…

What is the percent of Caco, in an antacid given that a tablet weighed 1.3198 g reacted with 50.00 ml of 0.4486 N HCI that subsequently required 3.72 ml of 0.1277 N NaOH for back titration? Also report the milligrams of Caco, in the tablet.

What is the percent of Caco, in an antacid given that a tablet weighed 1.3198 g reacted with 50.00 ml of 0.4486 N HCI that subsequently required 3.72 ml of 0.1277 N NaOH for back titration? Also report the milligrams of Caco, in the tablet.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

Show solution. Round off answer to four decimal places. Formula is given. Answer: % CaCO3 = _% weight of CaCO3 = _mg

N x V x mEq
sample weight(g)
% рurity
sx wt (g)
x 100
N =
mEq x mL of solution
= fM
[(N x V)acid – (N × V)base] × mEq
Sx wt (g)
% purity =
× 100
(V blank – V sample) × N × mEq
sample weight (g)
% purity :
X 100

What is the percent of Caco, in an antacid given that a tablet weighed 1.3198 g reacted with 50.00 ml of 0.4486 N HCI that
subsequently required 3.72 ml of 0.1277 N N2OH for back titration? Also report the milligrams of Caco, in the tablet.

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