3.What is the P-value of the chi-square test of independence? What is the P-value of the chi-square test of independence?Hint, pchisq(q= , df= , lower.tail = FALSE)MetastasisNo MetastasisBenzene Added481562Control (no Benzene)440380

The data is given by Metastasis No metastatis Total Added 481 (a) 562 (b) 1043 Control 440…

Answered: What is the P-value of the chi-square…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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K Previously, 6.6% of workers had a travel time to work of more than 60 minutes. An urban economist believes that the percentage has increased since then. She randomly selects 55 workers and finds that 10 of them have a travel time to work that is more than 60 minutes. Test the economist's belief at the x = 0.1 level of significance. What are the null and alternative hypotheses? Ho: ▼ versus H₁: (Type integers or decimals. Do not round.) Because npo (1-Po) (Round to one decimal place as needed.) Find the P-value. = 10, the normal model P-value= (Round to three decimal places as needed.) Is there sufficient evidence to support the economist's belief? 00 be used to approximate the P-value. OA. Yes, do not reject the null hypothesis. There is sufficient evidence because the P-value is greater than α. OB. No, do not reject the null hypothesis. There is not sufficient evidence because the P-value is greater than α. C. Yes, reject the null hypothesis. There is sufficient evidence because the…
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The degrees of freedom is critical to computing the p-value for the chi-square goodness of fit. We will discuss the p-value in the next lab. The degrees of freedom for the Chi-Square goodness of fit is equal to (the number of non-zero rows in the table) - 1. The number of non-zero rows is the number of expected values that are non-zero. For example: Phenotype ... Expected ... Disease ... 234 ... Wild-type ... 6743 ... has two rows where the Expected value is non-zero. So the degrees of freedom is 2-1 = 1. Another example: Phenotype ... Expected ... Disease ... 2374 ... Wild-type ... 0 ... has one row where the Expected value is non-zero. So the degrees of freedom is 1-1 = 0. With 0 degrees of freedom, the chi-square test cannot be calculated. A third example (sex-linked): Phenotype ... Expected ... Disease-Male ... 2374 ... Disease-Female ... 9456 Wild-type-Male ... 1001 ... Wild-type-Female ... 235 ... has four rows where the Expected values are…
Why is the Chi- square test applicable to the given scenario?
In a business, the Chief Executive Officer wants to know if his workers are for or against mandatory vaccinations. A random sample of 200 workers was taken and the results are shown in the MINITAB output below Expected counts are printed below observed counts Managers Team leaders Employees Total 17 22 15 Approve 21.330 17.820 14.850 54 34 25 14 Against 28.835 24.090 20.075 73 28 19 26 No Opinion 28.835 24.090 20.075 73 Total 79 66 55 200 Chi-sq = 0.878992 + 0.980494 + 0.001515 + 0.925168+ 0.034375 + 1.838387 + 0.02418 + 1.075471 + 1.74874 =7.507306
7[
Let X be a chi-squared random variable with 12 degrees of freedom. What is the probability that X is greater than 23? What are the steps to come to this conclusion?
For the chi-square test of independence, Provide a hypothetical formulation of test of independence.
J sampled 1000 people, and determined whether they are a teacher or not and their gender. J found the information in the following table. Is an Teacher Isn't an Teacher Male 42 449 Female 5 488 Other 1 15 Perform a chi-squared test of independence to test the null hypothesis that gender and status as an teacher are independent versus the alternative that they are dependent. What is the p-value for this test? What are the steps to come to this conclusion?
what is the chi-square test for goodness of fit for the study (use the 0.01 level)State the null and research hypotheses?Determine the cutoff sample score at which the null hypothesis should be rejected.?what is the cutoff score ? Solve for A-F based on the chart attached?
How do you test hypotheses with T-tests?

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