what is the p value?is the p-value low?can we conclude? SURVIVAL TIMESUse the Excel output to write out the conclusions of the Two-way Anova F-test, anduse a 5% significance level.Choose the options that will create the correct interaction conclusion.The interaction P-value of 0.00000033314 is low , so we conclude that there issignificant interaction between the two categorical variables.Answer 1:0.00000033314Answer 2:lowAnswer 3:conclude Data from "Statistics For Experimenters" by Box Hunter Hunter, 1978.The data ". appear in a paper by Box and Cox (1964). These are survival times ofgroups of four animals randomly allocated to three poisons and four treatments. Theexperiment was part of an investigation to combat the effects of certain toxic agents.This arrangement is called a 3 x 4 factorial design and is replicated four times."The aim here is to see how the different poisons and medications affect survivaltimes. Survival time is measured in ten-hours.Use the information provided below to answer the SURVIVAL TIMES questions thatfollow.Two wey Anove: SURVIVAL TIMES (DATA)MEDICATIONSMeans0.310420.430.450.45L10.450.710.61750.460.630.660.430.720.760620.360.920.440.560.290.610.351.02040.490.310.710.281.24040.380.220.230.210.370.250.360.27630.180.380.240.310.230.290.220.33Meana0.31420.67670.534204794Twoway Anova: SURVIVAL TIMES (EXCEL OUTPUT)Anova Twe facterSUMMARYATetalKountBum1653.522.272.44verage061Narience0.012733330.0436KountSum267Average0375as475NarianceCountSumverage1344.42021Nariance0.000TotalCount12121212Bum3.7741Average0.5341667Nariance0.0415379ANOVASeure of VeritienPualeFetSample3.25944602.10OL2S23.22163.34-07Kolam0.21202steractionG.800725360.02224236hotal3.005O125SNOSIO4

Answer 1: The intersection P-value is 0.11225061. Thus, the intersection P-value is 0.11225061.…

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what is the p value? is the p-value low? can we conclude?

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Author:Amos Gilat

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Section: Chapter Questions

Problem 1P

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Concept explainers

Confidence Intervals

When we calculate intervals in probability and statistics, it can be simply termed as finding out a confidence interval. The confidence interval is usually calculated from the data set which is observed. The value of the parameter that needs to be calculated is present here only.

Question

100%

what is the p value?

is the p-value low?

can we conclude?

SURVIVAL TIMES
Use the Excel output to write out the conclusions of the Two-way Anova F-test, and
use a 5% significance level.
Choose the options that will create the correct interaction conclusion.
The interaction P-value of 0.00000033314 is low , so we conclude that there is
significant interaction between the two categorical variables.
Answer 1:
0.00000033314
Answer 2:
low
Answer 3:
conclude

Data from "Statistics For Experimenters" by Box Hunter Hunter, 1978.
The data ". appear in a paper by Box and Cox (1964). These are survival times of
groups of four animals randomly allocated to three poisons and four treatments. The
experiment was part of an investigation to combat the effects of certain toxic agents.
This arrangement is called a 3 x 4 factorial design and is replicated four times."
The aim here is to see how the different poisons and medications affect survival
times. Survival time is measured in ten-hours.
Use the information provided below to answer the SURVIVAL TIMES questions that
follow.
Two wey Anove: SURVIVAL TIMES (DATA)
MEDICATIONS
Means
0.31
042
0.43
0.45
0.45
L1
0.45
0.71
0.6175
0.46
0.63
0.66
0.43
0.72
0.76
062
0.36
0.92
0.44
0.56
0.29
0.61
0.35
1.02
04
0.49
0.31
0.71
0.28
1.24
04
0.38
0.22
0.23
0.21
0.37
0.25
0.36
0.2763
0.18
0.38
0.24
0.31
0.23
0.29
0.22
0.33
Meana
0.3142
0.6767
0.5342
04794
Twoway Anova: SURVIVAL TIMES (EXCEL OUTPUT)
Anova Twe facter
SUMMARY
A
Tetal
Kount
Bum
165
3.52
2.27
2.44
verage
061
Narience
0.01273333
0.0436
Kount
Sum
267
Average
0375
as475
Nariance
Count
Sum
verage
134
4.42
021
Nariance
0.000
Total
Count
12
12
12
12
Bum
3.77
41
Average
0.5341667
Nariance
0.0415379
ANOVA
Seure of Veritien
Puale
Fet
Sample
3.2594460
2.
10OL2S
23.2216
3.34-07
Kolam
0.21202s
teraction
G.800725
36
0.02224236
hotal
3.005O125
SNOSIO4

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