What is the output when the following code is executed? X = 1; y = 1; switch (x + 1) { case 2: y = 2; default: y += 1; System.out.println( y ); O 2 3 O 1

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
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### What is the output when the following code is executed?

```java
x = 1; y = 1;
switch (x + 1) {
    case 2: y = 2;
    default: y += 1;
}
System.out.println(y);
```

- ○ 2
- ○ 3
- ○ 1

### Explanation

This code snippet demonstrates a `switch` statement in Java. 

1. **Variables Initialization:**
   - `x` is set to 1.
   - `y` is set to 1.

2. **Switch Statement:**
   - The statement evaluates `x + 1`, which is `2`.
   - It matches `case 2:`, setting `y = 2`.
   - Since there is no `break;` statement after the `case 2`, the program continues to the `default` block.
   - In the `default` block, `y` is incremented by 1 (`y += 1`), making `y = 3`.

3. **Output:**
   - The value of `y` is printed, resulting in `3`.

Thus, the correct answer is:

- ○ 3
Transcribed Image Text:### What is the output when the following code is executed? ```java x = 1; y = 1; switch (x + 1) { case 2: y = 2; default: y += 1; } System.out.println(y); ``` - ○ 2 - ○ 3 - ○ 1 ### Explanation This code snippet demonstrates a `switch` statement in Java. 1. **Variables Initialization:** - `x` is set to 1. - `y` is set to 1. 2. **Switch Statement:** - The statement evaluates `x + 1`, which is `2`. - It matches `case 2:`, setting `y = 2`. - Since there is no `break;` statement after the `case 2`, the program continues to the `default` block. - In the `default` block, `y` is incremented by 1 (`y += 1`), making `y = 3`. 3. **Output:** - The value of `y` is printed, resulting in `3`. Thus, the correct answer is: - ○ 3
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