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What is the output of the following code snippet? int* ptr; *ptr = *ptr + 5; cout << *ptr << endl; There is no output due to compilation errors. The address stored in ptr 5 It results in an unpredictable error when the code is run because it uses an uninitialized pointer

What is the output of the following code snippet? int* ptr; *ptr = *ptr + 5; cout << *ptr << endl; There is no output due to compilation errors. The address stored in ptr 5 It results in an unpredictable error when the code is run because it uses an uninitialized pointer

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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**Question:** What is the output of the following code snippet? ```cpp int* ptr; *ptr = *ptr + 5; cout << *ptr << endl; ``` **Options:** - There is no output due to compilation errors. - The address stored in ptr - 5 - It results in an unpredictable error when the code is run because it uses an uninitialized pointer --- **Explanation:** The code snippet initializes a pointer `ptr` of type `int*` but does not assign it an initial value, making it uninitialized. The next line attempts to dereference and assign a value to this pointer, which can lead to undefined behavior or runtime errors, as the pointer does not point to a valid memory location. The correct answer to the question is: - It results in an unpredictable error when the code is run because it uses an uninitialized pointer.
Transcribed Image Text:**Question:** What is the output of the following code snippet? ```cpp int* ptr; *ptr = *ptr + 5; cout << *ptr << endl; ``` **Options:** - There is no output due to compilation errors. - The address stored in ptr - 5 - It results in an unpredictable error when the code is run because it uses an uninitialized pointer --- **Explanation:** The code snippet initializes a pointer `ptr` of type `int*` but does not assign it an initial value, making it uninitialized. The next line attempts to dereference and assign a value to this pointer, which can lead to undefined behavior or runtime errors, as the pointer does not point to a valid memory location. The correct answer to the question is: - It results in an unpredictable error when the code is run because it uses an uninitialized pointer.
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