What is the output of the following code? public static void main(String[] args) { boolean flag1 = increaseTemp(30); boolean flag1 = plant(16); boolean flag2 = harvest(10); %3D System.out.println(flag1); System.out.println(flag2); if (!flag1 || !flag2) System. out. println("happy!!"):
What is the output of the following code? public static void main(String[] args) { boolean flag1 = increaseTemp(30); boolean flag1 = plant(16); boolean flag2 = harvest(10); %3D System.out.println(flag1); System.out.println(flag2); if (!flag1 || !flag2) System. out. println("happy!!"):
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Question
java
![### What is the output of the following code?
```java
public static void main(String[] args) {
boolean flag1 = increaseTemp(30);
boolean flag1 = plant(16);
boolean flag2 = harvest(10);
System.out.println(flag1);
System.out.println(flag2);
if (!flag1 || !flag2)
System.out.println("happy!");
if (flag1 || flag2)
System.out.println("sad!");
}
public static boolean plant(int x) {
boolean rightFlag;
if (x / 2 > 5)
rightFlag = true;
else
rightFlag = false;
return rightFlag;
}
public static boolean harvest(int x) {
boolean wrongFlag;
if (x <=0)
wrongFlag = true;
else
wrongFlag = false;
return wrongFlag;
}
```
### Detailed Explanation
#### **Code Explanation**
1. **Main Method**:
- There seems to be a typo, where two variables are declared with the same name (`flag1`). This would cause a compilation error. Assuming this is a typo and that the first `boolean flag1 = increaseTemp(30);` line is to be ignored or replaced with the appropriate logic.
2. `boolean flag1 = plant(16);`
- Calls the `plant` method with `x=16`
- `flag1` will be `true` if `x / 2 > 5`, i.e., `16 / 2 > 5` which is `8 > 5` (true), so `flag1` will be `true`.
3. `boolean flag2 = harvest(10);`
- Calls the `harvest` method with `x=10`
- `flag2` will be `true` if `x <= 0`, i.e., `10 <= 0` which is false, so `flag2` will be `false`.
4. **Output Statements:**
- `System.out.println(flag1);` will print `true`.
- `System.out.println(flag2);` will print `false`.
- The conditional `if (!flag1 || !flag2)` is true because `!flag2` is true (since `flag2` is false).
- This will print `happy!`.
- The conditional `if (flag1 ||](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F0e6f6223-c696-4938-9015-1aa854831435%2F23de9acf-692d-4c02-8f42-c16dd7e8689c%2Fqgvjr4e_processed.png&w=3840&q=75)
Transcribed Image Text:### What is the output of the following code?
```java
public static void main(String[] args) {
boolean flag1 = increaseTemp(30);
boolean flag1 = plant(16);
boolean flag2 = harvest(10);
System.out.println(flag1);
System.out.println(flag2);
if (!flag1 || !flag2)
System.out.println("happy!");
if (flag1 || flag2)
System.out.println("sad!");
}
public static boolean plant(int x) {
boolean rightFlag;
if (x / 2 > 5)
rightFlag = true;
else
rightFlag = false;
return rightFlag;
}
public static boolean harvest(int x) {
boolean wrongFlag;
if (x <=0)
wrongFlag = true;
else
wrongFlag = false;
return wrongFlag;
}
```
### Detailed Explanation
#### **Code Explanation**
1. **Main Method**:
- There seems to be a typo, where two variables are declared with the same name (`flag1`). This would cause a compilation error. Assuming this is a typo and that the first `boolean flag1 = increaseTemp(30);` line is to be ignored or replaced with the appropriate logic.
2. `boolean flag1 = plant(16);`
- Calls the `plant` method with `x=16`
- `flag1` will be `true` if `x / 2 > 5`, i.e., `16 / 2 > 5` which is `8 > 5` (true), so `flag1` will be `true`.
3. `boolean flag2 = harvest(10);`
- Calls the `harvest` method with `x=10`
- `flag2` will be `true` if `x <= 0`, i.e., `10 <= 0` which is false, so `flag2` will be `false`.
4. **Output Statements:**
- `System.out.println(flag1);` will print `true`.
- `System.out.println(flag2);` will print `false`.
- The conditional `if (!flag1 || !flag2)` is true because `!flag2` is true (since `flag2` is false).
- This will print `happy!`.
- The conditional `if (flag1 ||
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